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slamgirl [31]
2 years ago
13

A chemistry student adds a quantity of an unknown solid compound X to 5.00 L of distilled water at 15.° C . After 10 minutes of

stirring, only a little X has dissolved. The student then drains off the solution and evaporates the water under vacuum. A precipitate is left behind. The student washes, dries and weighs the precipitate. It weighs 0.17 kg.
Can you calculate the solubility of X in water at 15.° C
Chemistry
1 answer:
Yuliya22 [10]2 years ago
8 0

Answer:

34 g/100 mL

Explanation:

The solubility of a compound can be expressed in g/100mL, for this we must divide the mass of the compound that dissolves in the solute by the volume of the solvent.

The solvent, in this case, is water, and that mass of the solute X that dissolved is the mass that was recovered after the solvent was drained and evaporated. So the solubility of X (S) is:

S = 0.17 kg/5L

S = 170g/5000mL

S = 170g/(5*1000)mL

S = 34 g/100 mL

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A hypothetical covalent molecule, x–y, has a dipole moment of 1.44 d and a bond length of 163 pm. calculate the partial charge o
Aneli [31]
As we know,
                                     1 D  =  3.34 × 10⁻³⁰ C.m
So,
                                     1.44 D  =  ?
Solving for 1.44 D,
                                     =  (3.34 × 10⁻³⁰ C.m × 1.44 D) ÷ 1 D
                    
                         1.44 D  =  4.80 × 10⁻³⁰ C.m

Dipole Moment 
is given as,
 
                         Dipole Moment  =  q  ×  r    
Solving for q,
                         q  =  Dipole Moment / r    ------ (1)
Where,
                         Dipole Moment  =  4.80 × 10⁻³⁰ C.m

                         r  =  163 pm  =  1.63 × 10⁻¹⁰ m

Putting values in eq. 1,

                            q  =  4.80 × 10⁻³⁰ C.m / 1.63 × 10⁻¹⁰ m

                            q  =  2.94 × 10⁻²⁰ C

As,
                            1.602 × 10⁻¹⁹ C  =  1 e⁻
So,
                             2.94 × 10⁻²⁰ C  =  X e⁻

Solving for X,

                            X  =  (2.94 × 10⁻²⁰ C × 1 e⁻) ÷ 1.602 × 10⁻¹⁹ C

                                = 0.183 e⁻

Result:
           
So one element is containing + 0.183 e⁻ while the other element is containing - 0.183 e⁻.
4 0
3 years ago
Describe one example of an energy transformation in this diagram and explain why it is a transformation. Repeat this description
iren [92.7K]

Answer:

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Explanation:

here u go :P

8 0
3 years ago
Read 2 more answers
What was John Dalton's contribution to the development of the atomic theory?
Lorico [155]

John Dalton made some hypothesis about the structure of atom. He proposed that matter is composed of great number of indivisible particles called atoms they can neither be destroyed nor be created.

<h3>What is atomic theory?</h3>

There are different theories regarding the structure and electronic properties of an atom. Many scientists contributed to the modern theory of atomic structure in which John Dalton was first to mention the word atom.

According to Dalton' theory, matter is composed of indivisible particles called atoms. Atoms can neither be created nor be destroyed. All the atoms of the same element are identical in all aspects.

Atoms of different elements are different and the compounds are formed by the combination of atoms.  Dalton's theory provided a sound basis for the laws of chemical combination and also several properties of gases and liquids known at that time.

However, he could not explain the reason for chemical combination of atoms and did not give any idea about the existence of isotopes and isobars.

Hence, the main aspects of Dalton's theory was the indivisibility of atoms and the chances of chemical combination.

To learn more about Dalton's theory, find the link below:

brainly.com/question/11855975

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6 0
10 months ago
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VLD [36.1K]

Answer:

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Explanation:

Denote the element with a letter like say X. Since it has a subscript of 5, then, X5.

Molecular mass=102.133g/mol.

% of X in compound =58.8/100

=0.588

Mass of X in the compound = 0.588*102.133 ( the % of X in compound * molar mass of compound)

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X5=60.054204

Then element X has a mass of 60.054204/5=12.0108408

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DaniilM [7]

Answer:

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