0.164 g/L is the density of a sample of 1.00 mole of 
at 793mmhg and -9.00 degrees celcius.
<h3>What is density?</h3>
Density is the mass of a unit volume of a material substance. The formula for density is d = 
, where d is density, M is mass, and V is volume.
Given data:
n = 1.00 mole
P=793 mm hg =1.04342 atm
T=-9.00 degree celcius = -9.00 + 273= 264 K
V=?
Using Ideal Gas Law equation:
PV = n R T
R = gas constant = 0.082057 L-atm/(mol-K)
(1.04342 atm)(V) = 5 X 0.082057 L-atm/(mol-K) X 264 K
V = 103.67 Liters
Now calculate density:
Mole weight of = 1.00 mole
So, the mass of = 17.031 g
Density = 
Density = 
= 0.164 g/L
Hence, 0.164 g/L is the density of a sample of 1.00 mole of at 793mmhg and -9.00 degrees celcius.
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I think is is A. welding torches
Answer:
Remove exess water
Explanation:
The reaction involved is an esterification reaction. Esterification is a reaction in which alcohol and carboxylic acid reacts to yield an ester and water. It is analogous to the inorganic neutralization reaction.
According to Le Chatelier's principle , one method of driving the equilibrium towards the forward reaction is by removal of one of the products. In this case, if water is removed, the forward reaction is favoured.
Answer:
30 L H2
Explanation:
- 10 L N2 x <u>3 L H2</u> = 30 L H2
. 1 L N2
Try to verify my answer, Stoichiometry is not easy for me.
