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vovangra [49]
3 years ago
10

Imagine a drop of water in oil. If you add surfactant, explain how the surfactant molecules organize themselves around the water

drop?
Chemistry
1 answer:
Oduvanchick [21]3 years ago
4 0
If you add a surfactant in water-oil mixture, surfactant molecules would form micelles wherein the hydrophobic end of the surfactant faces inside the micelle while the hydrophilic end faces the water molecules. Inside these micelles oil particles are attached. 
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5.Are pure solids included in equilibrium expressions? Explain your answer.
tatiyna

Answer:

Pure solids or liquids are excluded from the equilibrium expression because their effective concentrations stay constant throughout the reaction. The concentration of a pure liquid or solid equals its density divided by its molar mass.

Explanation:

Hope this helps!!!

8 0
2 years ago
A neutral atom has 12 protons and 13 neutrons in its nucleus. What is its mass number?
Thepotemich [5.8K]

Answer: 68

Explanation: u times them

3 0
2 years ago
What two main characteristics are used to classify air masses
Klio2033 [76]
Temperature and Moisture 
8 0
3 years ago
Which statements are correct regarding the Law of Conservation of Matter and Energy?
Elden [556K]

Answer:

Matter or energy can change from one form to the other

Explanation:

The law of conservation of energy states that energy can neither be created nor destroyed but can only be transformed i.e. changed from one form to another. For example, mechanical energy can be changed to electrical energy.

Likewise, the law of conservation of mass/matter states that matter can not be destroyed or created but can change via physical or chemical means to conserve it. For example, matter can change from liquid state to gaseous state.

From the above two laws, it can be said that "matter or energy can change from one form to the other".

5 0
3 years ago
The half life of oxygen is 2 minutes. What fraction of a sample of 0.15 will remain after 5 half lives?​
Natasha_Volkova [10]

Answer:

3.13%.

Explanation:

The following data were obtained from the question:

Original amount (N₀) = 0.15

Half life (t½) = 2 mins

Number of half-life (n) = 5

Fraction of sample remaining =.?

Next, we shall determine the amount remaining (N) after 5 half-life. This can be obtained as follow:

Amount remaining (N) = 1/2ⁿ × original amount (N₀)

NOTE: n is the number of half-life.

N = 1/2ⁿ × N₀

N = 1/2⁵ × 0.15

N = 1/32 × 0.15

N = 0.15/32

N = 4.69×10¯³

Therefore, 4.69×10¯³ is remaining after 5 half-life.

Finally, we shall the fraction of the sample remaining after 5 half-life as follow:

Original amount (N₀) = 0.15

Amount remaining (N) = 4.69×10¯³

Fraction remaining = N/N₀ × 100

Fraction remaining = 4.69×10¯³/0.15 × 100

Fraction remaining = 3.13%

3 0
2 years ago
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