Answer: A comprehensive legal term for uniform standards ascribed to the quantity, capacity, volume, or dimensions of anything. Legislation that adopts and mandates the use of a uniform system of weights and measures is a valid exercise of Police Power, and such laws are constitutional.
Explanation:
Answer:
<h2><u><em>100 kcal of bond energy</em></u></h2>
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The total amount that Staci had in hand is $200.00.
The ticket at that time costs $87.96.
One Tshirt costs, $30.00.
Now that she has paid ticket, she will deduct the ticket from the cash she has in hand, so as to know the amount she is remaining with.
Tha is, $200-$87.96 = $112.04.
∴ In hand Staci has $112.04 extra cash whereby she can purchase more t shirts.
To get the number of tshirt she can buy, she will divide the amount she has in hand by the amount per piece of t shirt.
For example, $112.04 / $30 = $3.73.
∴ Staci can only purchase threet shirts only at a total cost of $90 for all the t shirts which is $30 × 3 = $90.
Staci has excess of 22.04 after deducting ticket and the other amount she has used to purchase the extra t shirts.
That is, $112.04 - $90 = $22.04.
Answer:
1. C + O₂ → CO₂
2. C + CO₂ → 2 CO
3. Fe₂O₃ + 3 CO → 2 Fe + 3 CO₂
Answer:
2. The metal would lose one electrons and the non metal would gain one electrons
Explanation:
An atom of a certain element reacts with the atoms of other elements in order to fullfill its outermost shell (called valence shell).
We notice the following:
- The elements in Group 1 (which are metals) have only 1 electron in their valence shell
- The elements in Group 17 (which are non-metals) have 1 vacancy (lack of electron) in their valence shell
This means that in order for both an atom of group 1 and an atom of group 17 to fullfill the valence shell, they have to:
- The atom in group 1 has to give away its only electron of the valence shell
- The atom in group 17 has to gain one electron in order to fullfill the shell
Therefore, the correct option is
2. The metal would lose one electrons and the non metal would gain one electrons
