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kenny6666 [7]
3 years ago
13

What is limiting about a liquid Mercury thermometer?

Chemistry
1 answer:
ella [17]3 years ago
8 0
There are non-mercury thermometers with temperature and accuracy rangers equal to most mercury thermometers.
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1. The molar mass of BeF2
oksano4ka [1.4K]

Answer:

47.01 g/mol is molar mass

8 0
3 years ago
Individual solute particles are broken apart from the solid by these particles. * a Solution b Insoluble c Solvent d Compounds
Maru [420]

Answer:

Individual solute particles are broken apart from the solid by the;

c. Solvent

Explanation:

A solution is the homogeneous mixture that is made up of two or more substances formed by dissolving a substance which can be a solid, liquid or gas in another substance known as the solvent which normally the larger part of the fraction of the solution than the solute and can also be a solid, liquid or a gas

In a solution the solvent particles serves to brake of and disperser parts of a solid solute to form a more or less homogeneous mixture

Therefore, the solute particles are broken by the <u>solvent</u> particles in a solution

7 0
3 years ago
If you have 85.0 grams of CO₂, calculate how many moles of CO₂ would you have?
dedylja [7]
N=m(g)/m.wt
n=85/12(1)+16(2) =1.93 moles
4 0
2 years ago
Read 2 more answers
Naturally occurring silicon has an atomic mass of 28.086 and consists of three isotopes. The major isotope is 28Si, natural abun
Elden [556K]

Answer:

29Si has a natural abundance of 4.68%.

30Si has a relative atomic mass of 29.99288 and a natural abundance of 3.09%.

Explanation:

The atomic mass of silicon is given by:

Si=Si²⁸×A₁+Si²⁹×A₂+Si³⁰×A₃

Where:

Si: atomic mass of silicon (28.086)

Si²⁸: relative atomic mass of 28Si (27.97693)

A₁: natural abundance of 28Si (92.23%)

Si²⁹: relative atomic mass of 29Si (28.97649)

A₂: natural abundance of 29Si

Si³⁰: relative atomic mass of 30Si

A₃: natural abundance of 30Si

We also know that 30Si natural abundance is in the ratio of 0.6592 to that of 29Si.

We have to set up a system of three equations in three unknowns:

Si=Si²⁸×A₁+Si²⁹×A₂+Si³⁰×A₃

A₃=0.6592×A₂

A₁+A₂+A₃=1

First, we find substitute the value of A₃ in the third equation and solv teh value of A₂:

A₁+A₂+0.6592×A₂=1

A₁+1.6592×A₂=1

1.6592×A₂=1-A₁

A₂=\frac{1-A₁}{1.6592}=\frac{1-0.9223}{1.6592}=0.0468

Then, we find the value of A₃:

A₃=0.6592×A₂

A₃=0.6592×0.0468=0.0309

Finally, we find the value of Si³⁰ in the first equation:

Si=Si²⁸×A₁+Si²⁹×A₂+Si³⁰×A₃

28.086=27.97693×0.9223+28.97649×0.0468+Si³⁰×0.0309

28.086=27.15922+Si³⁰×0.0309

28.086-27.15922=Si³⁰×0.0309

\frac{0.92678}{0.0309}=Si³⁰

Si³⁰=29.99288

8 0
3 years ago
How many grams of C3H8
Tresset [83]

Answer:

91.28 g

Explanation:

7 0
3 years ago
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