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dimaraw [331]
2 years ago
5

A train travels 8.81 m/s in a -51.0° direction.

Physics
1 answer:
Amiraneli [1.4K]2 years ago
8 0

The displacement of the train after 2.23 seconds is 25.4 m.

<h3>Resultant velocity of the train</h3>

The resultant velocity of the train is calculated as follows;

R² = vi² + vf² - 2vivf cos(θ)

where;

  • θ is the angle between the velocity = (90 - 51) + 37 = 76⁰

R² = 8.81² + 9.66² - 2(8.81 x 9.66) cos(76)

R² = 129.75

R = √129.75

R = 11.39 m/s

<h3>Displacement of the train</h3>

Δx = vt

Δx = 11.39 m/s x 2.23 s

Δx = 25.4 m

Thus, the displacement of the train after 2.23 seconds is 25.4 m.

Learn more about displacement here: brainly.com/question/2109763

#SPJ1

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3 0
3 years ago
The earth has a vertical electric field at the surface, pointing down, that averages 100 N/C. This field is maintained by variou
zlopas [31]

Answer:

q = 3.6 10⁵  C

Explanation:

To solve this exercise, let's use one of the consequences of Gauss's law, that all the charge on a body can be considered at its center, therefore we calculate the electric field on the surface of a sphere with the radius of the Earth

          r = 6 , 37 106 m

          E = k q / r²

          q = E r² / k

          q = \frac{100 \ (6.37 \ 10^6)^2}{9 \ 10^9}

          q = 4.5 10⁵ C

Now let's calculate the charge on the planet with E = 222 N / c and radius

           r = 0.6 r_ Earth

           r = 0.6 6.37 10⁶ = 3.822 10⁶ m

           E = k q / r²

            q = E r² / k

            q = \frac{222 (3.822 \ 10^6)^2}{ 9 \ 10^9}

            q = 3.6 10⁵  C

4 0
3 years ago
What is the magnetic field amplitude of an electromagnetic wave whose electric field amplitude is 10v/m?
Nitella [24]

Answer:

3.33\cdot 10^{-8} T

Explanation:

For an electromagnetic wave, the relationship between magnetic field amplitude and electric field amplitude is given by

E=cB

where

E is the amplitude of the electric field

c is the speed of light

B is the amplitude of the magnetic field

For the electromagnetic wave in this problem, we have

E = 10 V/m is the amplitude of the electric field

So if we solve the formula for B, we find the amplitude of the magnetic field:

B=\frac{E}{c}=\frac{10 V/m}{3\cdot 10^8 m/s}=3.33\cdot 10^{-8} T

4 0
3 years ago
A dog pushes against the front door for 3 seconds with a force of 88 N. What
kirill [66]

264Ns

Explanation:

Given parameters:

Time of the push = 3s

Force of push = 88N

Unknown:

Impulse = ?

Solution:

Impulse is defined as the change in momentum of a body when force acts on it.

  Impulse = Force x time

Inputting the parameters:

    Impulse = 88 x 3 = 264Ns

Learn more:

Momentum brainly.com/question/9484203

#learnwithBrainly

5 0
3 years ago
What is the frequency of the most intense radiation emitted by your body? assume a skin temperature of 95 ∘f?
navik [9.2K]

Answer:    
Wien's law:    
λ_peak = b/T    
Wien's constant: b = 2.8977685(51)Ă—10â’3 m•K    
T = (5/9)[96 – 32) + 273 = 35.55 + 273 = 308.55 deg. K    
λ_peak = 2.8977685(51)Ă—10â’3 /308.55 = 9.39x10^-6 = 9.39 um
7 0
3 years ago
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