The correct expression for the maximum speed of the object during its motion is
.
<h3>
Maximum speed of the object</h3>
The maximum speed of the object is determined using the following formulas;
v(max) = Aω
where;
- A is the amplitude of the motion
- ω is angular speed
The maximum speed of the object can also be obtained from the maximum net force on the object,
F = ma
where;
- F is the maximum net force
- a is the acceleration
- m is mass of the object
F = m(v/t)
mv = Ft
v = Ft/m
Thus, the correct expression for the maximum speed of the object during its motion is
.
Learn more about maximum speed here: brainly.com/question/4931057
B. number of oscillations in a given period of time.
<h3><u>
For the aceleration:</u></h3>
First, let's find the resultant, and <u>applicate 2nd law of Newton</u> using the resultant, so:
R = ma
F - Ff = ma
Data:
F = Force = 1150 N
Ff = Friction force = 490 N
m = Mass = 150 kg
a = Aceleraction = ?
Replacing according our data:
1150 N - 490 N = 150 kg * a
660 N = 150 kg * a
660 N / 150 kg = a
a = 4,4 m/s² ← Aceleration of the object
<h3><u>For the normal force:</u></h3>
The normal force IS NOT the resultant force, the normal force's the force between the ground and the object, in another words, is the weight of the object, and for the weight:
w = mg
w = 150 kg * 10 m/s²
w = 1500 N ← Normal force between object and ground.