Explanation:
F=15000/0.02
=300N
total area contact of the shoes and floor when stood in one foot=0.02m^2/2=0.01m^2
P=F/A
=300/0.01
=30 000Pa/30 000Nm^-2
in another way=15000×2
=30000N/m^2
Answer:
6.69 m/s
4.483 m
1.42s
Explanation:
Given that:
Initial Velocity, u = 0
Final velocity, v =?
Acceleration, a = 35m/s²
1.) using the relation :
v² = u² + 2as
v² = 0 + 2(35) * 64*10^-2m
v² = 70 * 0.64
v = sqrt(44.8)
v = 6.693
v = 6.69 m/s
B.) height from the ground, h0 = 2.2
How high ball went , h:
Using :
v² = u² + 2as
Upward motion, g = - ve
0 = 6.69² + 2(-9.8)*(h - 2.2)
0= 6.69² - 19.6(h - 2.2)
44.7561 + 43.12 - 19.6h = 0
19.6h = 44.7561 - 43.12
h = 87.8761 / 19.6
h = 4.483 m
C.)
vt - 0.5gt² = h - h0
6.69t - 0.5(9.8)t²
6.69t - 4.9t² = 1.83 - 2.2
-4.9t² + 6.69t + 0.37 = 0
Using the quadratic equation solver :
Taking the positive root:
1.4185 = 1.42s
Many people believe in the big bang theory but i believe God created the heavens and the earth with his own hands.
<span>Kinematics is used in this problem. The mass does not matter here because the question is mass independent.
vi = 0
vf = x
d = ?
d = vi + 1/2 a t^2
d = 0 + 1/2 (9.8) (1.8)^2
d = 15.9 m (counting sig figs)</span>
