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1 year ago

for number less than 0.1, such as 0.06, the zeros to the right of the decimal point but before the first nonzero digit

1 answer:

6 0

For the number less than 0.1 such as 0.006, the zeroes to the right of the decimal point but before the first non zero digit show the decimal place of the first significant digit.

The number that is given as digits is established using significant figures.
Any two non-zero digits that are separated by a zero are significant figure.
Every zero that is both to the right and left of a non-zero digit and the decimal point is not significant figure.
The quantity of significant figures frequently reveals the degree of measurement accuracy. From the first non-zero digits in the figure, we may determine the number of significant figures.

There is only one significant figure in the provided number 0.06. The decimal place of the first digit is indicated by the zeros that appear to the right of the decimal point but before the first non-zero digit.

Learn more about significant figure here:

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A solution is made using 200.0 mL of methanol (density 0.792 g/mL) and 985.1 mL of water (density 1.000 g/mL). What is the mass

DaniilM [7]

Answer: The mass percent of methanol in solution is 13.85 %

Explanation:

To calculate the mass of water, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

For water:

Density of water = 1.000 g/mL

Volume of water = 985.1 mL

Putting values in above equation, we get:

$1.000g/mL=\frac{\text{Mass of water}}{985.1mL}\\\\\text{Mass of water}=(1.000g/mL\times 985.1mL)=985.1g$

For methanol:

Density of methanol = 0.792 g/mL

Volume of methanol = 200.0 mL

Putting values in above equation, we get:

$0.792g/mL=\frac{\text{Mass of methanol}}{200.0mL}\\\\\text{Mass of methanol}=(0.792g/mL\times 200.0mL)=158.4g$

To calculate the mass percent of methanol, we use the equation:

$\text{Mass percent of methanol}=\frac{\text{Mass of methanol}}{\text{Mass of solution}}\times 100$

Mass of solution = [158.4 + 985.1] g = 1143.5 g

Mass of methanol = 158.4 g

Putting values in above equation, we get:

$\text{Mass percent of methanol}=\frac{158.4g}{1143.5g}\times 100=13.85\%$

Hence, the mass percent of methanol in solution is 13.85 %

3 0

3 years ago

I2(g) + Cl2(g)2ICl(g) Using standard thermodynamic data at 298K, calculate the entropy change for the surroundings when 1.62 mol

galina1969 [7]

Answer:

The change in entropy of the surrounding is -146.11 J/K.

Explanation:

Enthalpy of formation of iodine gas = $\Delta H_f_{(I_2)}=62.438 kJ/mol$

Enthalpy of formation of chlorine gas = $\Delta H_f_{(Cl_2)}=0 kJ/mol$

Enthalpy of formation of ICl gas = $\Delta H_f_{(ICl)}=17.78 kJ/mol$

The equation used to calculate enthalpy change is of a reaction is:

$\Delta H_{rxn}=\sum [n\times \Delta H_f(product)]-\sum [n\times \Delta H_f(reactant)]$

For the given chemical reaction:

$I_2(g)+Cl_2(g)\rightarrow 2ICl(g),\Delta H_{rxn}=?$

The equation for the enthalpy change of the above reaction is:

$\Delta H_{rxn}=[(2\times \Delta H_f_{(ICl)})]-[(1\times \Delta H_f_{(I_2)})+(1\times \Delta H_f_{(Cl_2)})]$

$=[2\times 17.78 kJ/mol]-[1\times 0 kJ/mol+1\times 62.436 kJ/mol]=-26.878 kJ/mol$

Enthaply change when 1.62 moles of iodine gas recast:

$\Delta H= \Delta H_{rxn}\times 1.62 mol=(-26.878 kJ/mol)\times 1.62 mol=-43.542 kJ$

Entropy of the surrounding = $\Delta S^o_{surr}=\frac{\Delta H}{T}$

$=\frac{-43.542 kJ}{298 K}=\frac{-43,542 J}{298 K}=-146.11 J/K$

1 kJ = 1000 J

The change in entropy of the surrounding is -146.11 J/K.

4 0

3 years ago

17) Chlorine and Fluorine react to form gaseous chlorine trifluoride. You start with 1.75 mole of chlorine and 3.68 moles of flu

Mama L [17]

Answer:

a) $Cl_2 + 3F_2 \rightarrow 2ClF_3$

b) $F_2$ is the limiting reagent

c) Moles of $ClF_3$ produced = 2.45 mol

b) Moles of $Cl_2$ left = 1.75 -1.22 = 0.53

Explanation:

a) Balanced reaction:

$Cl_2 + 3F_2 \rightarrow 2ClF_3$

No. of mole of $Cl_2 = 1.75\ mol$

No. of mole of $F_2 = 3.68\ mol$

$Cl_2 + 3F_2 \rightarrow 2ClF_3$

As, it is clear from the reaction that,

1 mol of $Cl_2$ requires 3 moles of $F_2$

1.75 mol of $Cl_2$ require = 1.75 × 3 = 5.25 mol of $F_2$

As, only 3.68 mol of $F_2$ is present, so $F_2$ is the limiting reagent.

3 moles of $F_2$ form 2 moles of $ClF_3$

3.68 moles of $F_2$ will form = $\frac{2}{3} \times 3.68 = 2.45\ mol\ of\ ClF_3$

$Cl_2$ is present in excess.

3 moles of $F_2$ requires 1 mol of $Cl_2$

3.68 moles of $F_2$ will require = $\frac{1}{3} \times 3.68 = 1.22\ mol\ of\ Cl_2$

$Cl_2$ left = 1.75 -1.22 = 0.53 mol

6 0

4 years ago

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Which of the following compounds is not likely to have ionic bonds LiF, NaCI, CH4, MgF2

Rina8888 [55]

Methane CH $_{4}$ does not have ionic bonds. Because of the close value of electronegativity of the carbon and hydrogen atoms the electrons are shared forming covalent bonds.

3 0

3 years ago

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Pls 50 points right answer gets brainliest

GuDViN [60]

Answer:

thermal energy: the part of total internal energy that can be transferred (a portion of the kinetic energy)

heat is the thermal energy that flows from one substance to another due to a temperature difference.

Thermal energy is measured in temperature change.

Thermal energy transfer stops when thermal equilibrium is achieved (Both substances at the same temperature).

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convection: the transfer of thermal energy due to the movement of a liquid or gas caused by differences in temperature. Only in a fluid (liquid or gas). Breezes, ocean currents.

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7 0

3 years ago

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