The balanced equation
for the reaction is
CO(g) + 2H₂(g) ⇄ CH₃OH(g)
The given
concentrations are at equilibrium state. Hence we can use them directly in
calculation with the expression for the equilibrium constant, k.
expression for k can be written as
k = [CH₃OH(g)] / [CO(g)] [H₂<span>(g) ]²
</span>[H₂<span>]=0.072 M
[CO]= 0.020M
[CH</span>₃OH]= 0.030 M
From substitution,
k = 0.030
M / 0.020 M x (0.072 M)²
k =
289.35 M⁻²
<span>
Hence, equilibrium constant for the given reaction at 700 K is 289.35 M</span>⁻².
<span> </span>
Well one characteristic gases and the state of matter(one of the distinct form i which matter exist)
The alkali metals, which occupy group 1 of the periodic table. This is because the valence shells of these elements have only 1 electron, so easily form an ionic bond with a non-metal compound by donating this. A cation is formed by this donation, since there is one fewer electron orbiting the nucleus than there is in the atomic form - conversely an anion is formed when an atom gains an extra electron to become negatively charged.
The type of reaction in the example below is a double replacement.
A double replacement can be identified by the switch between two reactants. This can be verified because both a Br and Cl are being switched to a new position in the reaction.
The first one a neutral neutron strikes a large neutral nucleus
