All categories

3 years ago

Tungsten is used in light bulbs because its high...

2 answers:

6 0

Tungsten is used in light bulbs because of its high melting point.

It is also used because it has the lowest vapor pressure and greatest tensile strength.

ch4aika [34]3 years ago

4 0

Answer:

$\large \boxed{\mathrm{melting \ point}}$

Explanation:

Tungsten is used in light bulbs because its high melting point. Tungsten has a high melting point of $\sf 3422 \ \°C$ .

Tungsten also has the lowest vapor pressure and the highest tensile strength out of all the metals.

You might be interested in

Part 1 of 1 - Question 3 of 20 5.0 Points 2H2 O2 - > 2H2O can be classified as what type of reaction?

mart [117]

2 H₂ + O₂ = 2 H₂O

Answer B only synthesis.

hope this helps!

7 0

3 years ago

Plants and animals use different energy storage molecules, yet they both use the same mechanism to "burn" their stored energy. H

jek_recluse [69]

Answer:

The breaking of the chemical bonds of a storage molecule transfer energy, no what molecule is stored.

Explanation:

Being successful of plants and animals does not necessary depend on the stored molecule but on the energy being transferred during their breaking.

8 0

3 years ago

The diagram below shows Earth, four different positions of the Moon, and the direction of incoming sunlight.

Allisa [31]

Answer:

im 99% sure its 2

Explanation:

7 0

3 years ago

What is the conjugate acid of HCO3- ?OH-H2CO3CO32-H2OH3O+

adell [148]

<u>Answer:</u> The conjugate acid of $HCO_3^-$ is $H_2CO_3$

<u>Explanation:</u>

According to the Bronsted-Lowry conjugate acid-base theory:

An acid is defined as a substance which looses donates protons and thus forming conjugate base.
A base is defined as a substance which accepts protons and thus forming conjugate acid.

To form a conjugate acid of $HCO_3^-$ , this compound will accept one proton to form $H_2CO_3$

The chemical equation for the formation of conjugate acid follows:

$HCO_3^-+H^+\rightarrow H_2CO_3$

The conjugate acid formed is named as carbonic acid.

Hence, the conjugate acid of $HCO_3^-$ is $H_2CO_3$

5 0

4 years ago

What is the density of a piece of metal in g/cm3 if its mass is determined to be 42.20 g and it is in the shape of a cube, with

maria [59]

It's a cube so the volume = edge^3
Volume = 2.5^3 cm^3 = 15.625 cm^3

density = mass / volume = 42.20 / 15.625 = 2.70 You have 3 places of accuracy.

density of object = 2.70 grams / cm^3 <<<<=== answer.

4 0

3 years ago

Read 2 more answers