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Ronch [10]
2 years ago
15

Approximating the eye as a single thin lens 2. 75 cmcm from the retina, find the eye's near-point distance if the smallest focal

length the eye can produce is 2. 20 cm.
Physics
1 answer:
RSB [31]2 years ago
5 0

The near-point distance of the eye is 11 cm.

<h3>What is the eye's near-point distance?</h3>

The near-point distance of the eye is the closest possible distance an object can be from the eye in order for its image to be formed on the retina. It can also be termed the closest distance of accommodation.

The near-point distance of the eye in the given scenario can be calculated using the lens formula given below:

1/f = 1/v + 1/u

where;

f = focal length

v = image distance

u = object distance

From the data provided;

f = 2.20 cm

v = 2.75 cm

u = ?

Solving for u:

1/u = 1/f - 1/v

1/u = 1/2.20 - 1/2.75

1/u = 0.91

u = 11 cm

In conclusion, the lens formula is used to determine the eye's near-point distance.

Learn more about eye's near-point distance at: brainly.com/question/16391605

#SPJ1

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Answer:

The equation for momentum of a piece of matter.

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Explanation:

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4 0
2 years ago
Vector A has magnitude 8.00 mm and is in the xy-plane at an angle of 127∘ counterclockwise from the +x–axis (37∘ past the +y-axi
Ilia_Sergeevich [38]

Answer:

-75.35°

Explanation:

Let C be the sum of the two vectors A and B. Hence, we can write the following  

A_{x} +B_{x} =C_{x} ......(1)\\A_{y} +B_{y} =C_{y} ......(2)

but since the vector C is in the -y direction, C_{x}  = 0 and C_{y} = —12 m.  

Thus  

B_{x} =-A_{x} =-[-Acos(180-127)]=(8)*cos(53)\\B_{x} =4.81m

similarly, we can determine B_{y} by rearranging equation (1)  

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so the magnitude of B is

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Finally, the direction of B can be calculated as follows  

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8 0
4 years ago
What do we mean when we describe forces as balanced?
aivan3 [116]

Well, first, let's recognize that there is no such thing as a force that is
balanced or unbalanced.

When we say that a group of two or more forces is balanced, we mean
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3 0
3 years ago
In a circult, a battery is used to
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A 66-kg fellow stands on a digital scale in an elevator that accelerates upwards from rest to 4.5 m/s in 2.00 s. show answer Inc
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Answer:

Explanation:

mass of the fellow ( m ) = 66kg

acceleration of fellow a

v = u + at

4.5 = 0 + a x 2

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= 2.25 m / s²

Net force acting on fellow in upward direction by the surface of  elevator

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3 years ago
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