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IrinaK [193]
3 years ago
6

More current makes a ________ electromagnet. longer stronger weaker

Physics
2 answers:
Taya2010 [7]3 years ago
7 0

Answer: Stronger

Explanation:

I just took it

Fantom [35]3 years ago
4 0

Answer:

b

Explanation:

i did it on usa test prep

You might be interested in
Electromagnetic waves all move at the same wave speed. which of these offer solutions to slowing them down select all that apply
Lelechka [254]

option c...have the waves move thru the vacuum or space

6 0
3 years ago
What is the Gravitational Potential Energy of a 30 kg box lifted 1.5 meters off the ground?
juin [17]

Answer:

<h2>441 J</h2>

Explanation:

The potential energy of a body can be found by using the formula

PE = mgh

where

m is the mass

h is the height

g is the acceleration due to gravity which is 9.8 m/s²

From the question we have

PE = 30 × 9.8 × 1.5

We have the final answer as

<h3>441 J</h3>

Hope this helps you

6 0
3 years ago
What is the current through a 11v bulb with a power of 99w
Murrr4er [49]

Answer:

9.01amp

Explanation:

Power = V^2/R

Given that v = 11volts, P = 99watts

99 = 11^2/R

11×11 = 99R

121= 99R

R = 121/99

R= 1.22ohms

From ohms Law; V = IR

11volts = I × 1.22ohms

I = 11/1.23

I = 9.01 amp

8 0
3 years ago
Come si esprime il numero 0,00123 in notazione scientifica?
Inessa [10]

Answer:

0,00123 = 1,2*10^{-3}

Explanation:

To write down correctly the number 0,00123 in scientific notation, you take into account that the scientific notation demands that there in only one number after the comma ( , ). Furthermore, it is necessary that you move the comma to the right of the first number different of zero, in this case the number 1. To do this you move the comma three positions.

Then, you have to multiply the expresion 1.23 by 10 with an exponential -3 (because of the movement of the comma in three positions). That is:

0,00123 = 1,23*10^{-3}

But it is mandatory that nly one number can stay after the comma, so, you approximate the number three. In this case, the number is lower than 5, hence, you approximate 3 to 0.

Finally, you have:

0,00123 = 1,2*10^{-3}

3 0
3 years ago
A photon with an energy E = 2.12 GeV creates a proton-antiproton pair in which the proton has a kinetic energy of 96.0 MeV. What
Oksanka [162]

Answer:

The kinetic energy of the anti proton is 147.4 MeV.

Explanation:

Given that,

Energy = 2.12 GeV

Kinetic energy = 96.0 MeV

We need to calculate the kinetic energy of the anti proton

Using formula of energy

E_{photon}=m_{p}c^2+m_{np}c^2+K.E_{p}+K.E_{np}

We know that,

m_{p}c^2=m_{np}c^2

So, E_{photon}=2mc^2+K.E_{p}+K.E_{np}

K.E_{np}=E_{photon}-(2mc^2+K.E_{p})

Put the value into the formula

K.E_{np}=2.12\times10^{9}-2\times938.3\times10^{6}-96\times10^{6}

K.E_{np}=147.4\ MeV

Hence, The kinetic energy of the anti proton is 147.4 MeV.

6 0
3 years ago
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