Autonomic, but I don’t know why! Research this if you can.
The Gravitational PE (U) depends on three things: the object’s mass (m), its height (h), and gravitational acceleration (g), which is 9.81 m/s^2 on Earth’s surface.
so U = mgh = 9.81mh on earth
mass of the car = 50.0 grams = 0.05kg
height, h:
Hill 1 = 90.0 cm = 0.9m,
Hill 2 = 65.0 cm = 0.65m,
Hill 3 = 20.0 cm = 0.2m
substitute into eqn U = mgh
U @ top of Hill 1 = 0.05*9.81*0.9 = 0.4415J
U @ top of Hill 2 = 0.05*9.81*0.65 = 0.3188J
U @ top of Hill 3 = 0.05*9.81*0.2 = 0.0981J
difference in Gravitational Potential Energy from the top of Hill 1 to the top of Hill 3 = 0.4415 - 0.0981
= 0.3434J where J is the unit for energy, Joules
Answer:
v₁ = 4 [m/s].
Explanation:
This problem can be solved by using the principle of conservation of linear momentum. Where momentum is preserved before and after the missile is fired.

where:
P = linear momentum [kg*m/s]
m = mass [kg]
v = velocity [m/s]

where:
m₁ = mass of the tank = 500 [kg]
v₁ = velocity of the tank after firing the missile [m/s]
m₂ = mass of the missile = 20 [kg]
v₂ = velocity of the missile after firing = 100 [m/s]
![(500*v_{1})=(20*100)\\v_{1}=2000/500\\v_{1}=4[m/s]](https://tex.z-dn.net/?f=%28500%2Av_%7B1%7D%29%3D%2820%2A100%29%5C%5Cv_%7B1%7D%3D2000%2F500%5C%5Cv_%7B1%7D%3D4%5Bm%2Fs%5D)
There is no displacement. The frog is back where it began.
Answer:
It involves observation
It involves experimentation
It is supported by evidence
Explanation:
Science can be described as a system of knowledge based on the understanding of the natural world. The subject of science requires the scientific method - a chronological series of steps that have to be followed while trying to understand events in the natural world. These steps are:
- <em>observation</em>
- <em>formulation of hypothesis</em>
- <em>testing of the hypothesis by experimentation</em>
- <em>conclusion based on available evidence from the experiment</em>
Hence, science involves <u>observation</u>, <u>experimentation</u>, and <u>it is supported by evidence</u>.