Answer:
"0.053457 M" of sulfuric acid.
Explanation:
The given values are:
= 10 mL solution
= 12.20 mL
= 22.20 mL
then,
M 0.103 M of NaOH,
= experiment will not be affected
= 10.38 mL
Now,
⇒ mol of NAOH = MV
= 
= 
Whether Sulfuric acid, then
⇒ 
⇒ 
⇒ 
Before any dilution:

⇒ 

(Sulfuric acid)
Explanation:
34.2g of C12H22O11 is dissolved in 180g of H20.
Molar mass of sucrose = 342g/mol
Moles of sucrose = 342 / 34.2 = 10 mol.
Molar mass of water = 18g/mol
Moles of water = 180 / 18 = 10 mol.
For hydrogen atoms, there are 22 * 10 in sucrose and 2 * 10 in water, which gives a total of 240.
For oxygen atoms, there are 11 * 10 in sucrose and 1 * 10 in water, which gives a total of 120.
First one is a
the
second one is b
Answer:
B) Stainless steel
Explanation:
Homogeneous mixture -
It refers to the composition of various substance , which leads to a mixture of complete uniform composition , i.e. , the ratio of each and every component of the mixture is constant all over the mixture , is referred to as a homogeneous mixture.
For example ,
In the solution of sugar and water , where 1 tablespoon of sugar is dissolved in 100 mL of water ,
The ratio of sugar and water remains constant all over the mixture.
Hence, from the given options the homogeneous mixture is B) Stainless steel .
The mass in grams of NH₃ produced from the reaction is 3.4 g
<h3>Balanced equation</h3>
We'll begin by writing the balanced equation for the reaction. This illustrated below:
N₂ + 3H₂ -> 2NH₃
From the balanced equation above,
1 dm³ of N₂ reacted to produced 2 dm³ NH₃
<h3>How to determine the volume of NH₃ produced</h3>
From the balanced equation above,
1 dm³ of N₂ reacted to produced 2 dm³ NH₃
Therefore,
2.24 dm³ of N₂ will react to produce = 2.24 × 2 = 4.48 dm³ of NH₃
<h3>How to determine the mass of NH₃ produced</h3>
We'll begin by obtained the mole of 4.48 dm³ of NH₃. Details below:
22.4 dm³ = 1 mole NH₃
Therefore,
4.48 dm³ = 4.48 / 22.4
4.48 dm³ = 0.2 mole of NH₃
Finally, we shall determine the mass of NH₃ as follow:
- Molar mass of NH₃ = 17 g/mol
- Mole of NH₃ = 0.2 mole
- Mass of NH₃ =?
Mass = mole × molar mass
Mass of NH₃ = 0.2 × 17
Mass of NH₃ = 3.4 g
Learn more about stoichiometry:
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