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professor190 [17]
3 years ago
9

223Ra decays by alpha emission with a half-life of 11.43 days. For a 1.0g sample of 223Ra, after one half-life, what mass of 223

Ra remains? What has happened to the remaining mass?
Chemistry
1 answer:
Ray Of Light [21]3 years ago
6 0

Explanation:

The reaction that shows the alpha decay of ^{223}_{88}Ra is:

^{223}_{88}Ra\rightarrow ^{219}_{86}Rn+^{4}_{2}He

Half life is the time at which the concentration of the reactant reduced to half. So,

Mass\ of\ ^{223}_{88}Ra\ remained=\frac {Initial\ concentration}{2}=\frac {1.0\ g}{2}=0.5\ g

The remaining mass is converted to ^{219}_{86}Rn.

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The concentration of an HCl acid solution is initially 6mol/L. What would the concentration of a new solution be if 200 mL of th
pochemuha

Taking into account the definition of dilution, the concentration of the new solution is 1 mol/L.

<h3>Dilution</h3>

When it is desired to prepare a less concentrated solution from a more concentrated one, it is called dilution.

Dilution is the process of reducing the concentration of solute in solution, which is accomplished by simply adding more solvent to the solution at the same amount of solute.

In a dilution the amount of solute does not change, but as more solvent is added, the concentration of the solute decreases, as the volume (and weight) of the solution increases.

A dilution is mathematically expressed as:

Ci×Vi = Cf×Vf

where

  • Ci: initial concentration
  • Vi: initial volume
  • Cf: final concentration
  • Vf: final volume

<h3>Final volume</h3>

In this case, you know:

  • Ci= 6 mol/L
  • Vi= 200 mL
  • Cf= ?
  • Vf= 1 L (1000 mL) water + 200 mL of HCL= 1200 mL

Replacing in the definition of dilution:

6 mol/L× 200 mL= Cf× 1200 mL

Solving:

(6 mol/L× 200 mL)÷ 1200 mL= Cf

<u><em>1 mol/L= Cf</em></u>

In summary, the concentration of the new solution is 1 mol/L.

Learn more about dilution:

brainly.com/question/6692004

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5 0
1 year ago
What is the daughter nuclide when 0-15 experiences positron emission?
Helen [10]

The daughter isotope (a decay product)of O-15 = N-15(Nitrogen 15)

<h3>Further explanation </h3>

Radioactivity is the process of unstable isotopes to stable isotopes by decay, by emitting certain particles,  

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  • beta β ₋₁e⁰ particles
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O-15 emits positron particles ₁e⁰, so the atomic number decreases by 1, the mass number is the same

Reaction

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The mass number of the daughter isotope = 15, atomic number = 7

If we look at the periodic system, the element with atomic number 7 is Nitrogen (N)

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How is helium different from other noble gases?
Slav-nsk [51]
Helium only possesses two valence electrons, while the other noble gasses posses eight
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Anastaziya [24]

Answer:

I think it's B

Explanation:

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