Ask question

Ask question

All categories

3 years ago

11

What charge do Group 2 elements develop when they become ions? helppp :)

1 answer:

nalin [4]3 years ago

5 0

To illustrate, an atom of an alkali metal (group 1) loses one electron and forms a cation with a 1+ charge; an alkaline earth metal (group 2) loses two electrons and forms a cation with a 2+ charge, and so on. For example, a neutral calcium atom, with 20 protons and 20 electrons, readily loses two electrons.
Explanation: As you know, neutral atoms become ions by losing or by gaining electrons. ... In this case, elements located in group 2 will always lose electrons to become cations. More specifically, they will always lose 2 electrons to form 2+ cations.

You might be interested in

HELP PLEASE! EASY! How many stars does the barred-spiral galaxy contain?

Zepler [3.9K]

<span> Bars are found in approximately two-thirds of all spiral galaxies.</span>

5 0

3 years ago

Read 2 more answers

3. What are the energy levels of electrons?

KiRa [710]

Energy levels inside an atom are the specific energies that electrons can have when occupying specific orbitals.

7 0

3 years ago

Why do health care professionals limit the number of radiation treatments that a person can be given

katovenus [111]

Radiation is s very powerful substance and can cause major health problems do the health care professionals limit the use to help not create sickness

6 0

4 years ago

What do you think will happen if you pinch your arm after you stub your toe?

Maru [420]

It would distract the pain in your toe. That's all I got

6 0

3 years ago

Read 2 more answers

A solution of phosphoric acid was made by dissolving 10.0 g of H3PO4 in 100.0 mL of water. The resulting volume was 113 mL. Calc

rodikova [14]

Explanation:

Mass of solute = 10.0 g

mass of solvent(water) = m

Volume of solvent( water) = v = 100.0 mL

Density of water= d = $1 g/cm^3=1 g/mL$

$1 mL= 1 cm^3$

$m=d\times v=1.0 g/mL\times 100.0 = 100.0 g$

Mass of solution(M) = Mass of solute + mass of solvent

M = 10.0 g + 100.0 g = 110.0 g

Volume of the solution = V = 113 mL

Density of the solution = D

$D=\frac{M}{V}=\frac{110.0 g}{113 mL}=0.9734 g/mL$

The density of the solution is 0.9734 g/ml.

Moles of phosphoric acid = $n_1=\frac{10.0 g}{98 g/mol}=0.1020 mol$

Moles of water = $n_2=\frac{100.0 g}{18g/mol}=5.556 mol$

Mole fraction of phosphoric acid = $\chi_1$

$\chi_1=\frac{n_1}{n_1+n_2}=\frac{0.1020 mol}{0.1020 mol+5.556 mol}$

$\chi_1=0.01803$

Mole fraction of water = $\chi_2$

$\chi_2=\frac{n_2}{n_1+n_2}=\frac{5.556 mol}{0.1020 mol+5.556 mol}$

$\chi_2=0.9820$

$[Molarity]=\frac{\text{Moles of solute}}{\text{Volume of solution(L)}}$

Moles of phosphoric acid = 0.1020 mol

Volume of the solution = V = 113 mL = 0.113 L ( 1 mL = 0.001 L)

Molarity of the solution :

$=\frac{0.1020 mol}{0.113 L}=0.903 M$

$[Molality]=\frac{\text{Moles of solute}}{\text{Mass of solvent(kg)}}$

Moles of phosphoric acid = 0.1020 mol

Mass of solvent(water) = m =100.0 g = 0.100 kg ( 1 g = 0.001 kg)

Molality of the solution :

$=\frac{0.1020 mol}{0.100 kg}=1.02 mol/kg$

6 0

3 years ago