Given Information:
Voltage of circuit A = Va = 208 Volts
Current of circuit A = Ia = 40 Amps
Voltage of circuit B = Vb = 120 Volts
Current of circuit B = Ib = 20 Amps
Required Information:
Ratio of power = Pa/Pb = ?
Answer:
Ratio of power = Pa/Pb = 52/15
Explanation:
Power can be calculated using Ohm's law
P = VI
Where V is the voltage and I is the current flowing in the circuit.
The power delivered by circuit A is
Pa = Va*Ia
Pa = 208*40
Pa = 8320 Watts
The power delivered by circuit B is
Pb = Vb*Ib
Pb = 120*20
Pb = 2400 Watts
Therefore, the ratio of the maximum power delivered by circuit A to that delivered by circuit B is
Pa/Pb = 8320/2400
Pa/Pb = 52/15
<span>F=ma = 3000x2m/sec^2 =6000 newtons. </span>
Answer:
From the negative to the positive cable.
Explanation:
The electrons have negative charge, which means that the negative terminal of the battery will suply the electrons, thus they are present in excess on the negative cable and will jump from it to the positive cable. This current direction is called real current.
Answer:
Wavelength, 
Explanation:
Given that,
Mass of the particle, 
Acceleration of the particle, 
Time, t = 5 s
It starts from rest, u = 0
The De Broglie wavelength is given by :
v = a × t
Hence, this is the required solution.
Answer:
I don't know but I will try:
because the red color from the density column.
