<h2>Displacement to hole from initial position is 8.78 m at direction 42.23° south of east.</h2>
Explanation:
Let east represent X axis and north represent Y axis.
We need to find what displacement would put the ball in the hole in one putt.
The first putt displaces the ball 6.50 m east
First displacement = 6.50 i m
The second putt displaces it 5.90 m south
Second displacement = -5.90 j m
Total displacement = 6.50 i - 5.90 j
So displacement to hole from initial position is 8.78 m at direction 42.23° south of east.
The answer for this problem is clarified through this, the
system is absorbing (+). And now see that it uses that the SURROUNDINGS are
doing 84 KJ of work. Any time a system is overshadowing work done on it by the
surroundings the sign will be +. So it's just 12.4 KJ + 4.2 = 16.6 KJ.
Do u have the statements ?
The the object that has the less mass will travel faster because let’s say for example the first object has the mass of M and the second object has the mass of 2M and if the momentum is equal so that means that we could divide M with M and we would get V1=2V2 (being V1 the velocity of the first mass and V2 the velocity of the second one) I hope I helped you out.
