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OverLord2011 [107]
1 year ago
15

A Van de Graaff generator produces a beam of 2.00-MeV deuterons, which are heavy hydrogen nuclei containing a proton and a neutr

on. (b) Is the electrical force of repulsion among them a significant factor in beam stability? Explain.
Physics
1 answer:
Triss [41]1 year ago
6 0

The electrical force of repulsion among the deuterons is <u>not  a significant factor  </u>this is because the distance apart due to the repulsive force is small

<h3>what are deuterons?</h3>

A deuteron is the nucleus of an isotope of hydrogen. This is usually made up of one proton and on neutron. Deuterons is applied in nuclear reactions as projectiles

from kinetic energy k = 0.5 mv^2

v^2 = 2k / m

v^2 = ( 2 * 2MeV ) / ( 2 * 1.67E-27 )

mass of hydrogen = 2 * 1.67E-27

1 MeV = 1.6E+13 J

v^2 = ( 4 * 1.6E+13 ) / ( 2 * 1.67E-27 )

v = sqrt  ( 4 * 1.6E+13 ) / ( 2 * 1.67E-27 )

v= 1.38E+7 m/s

current I = charge q / time t

t = q / I

t = 1.67E-27 / 10E*-6

t = 1.6E-14 s

distance d

d = v * t

=  1.38E+7 * 1.6E-14

= 2.21E-7 m

The electrical force of repulsion in the deuterons is of less significant effect because the distance apart due to the repulsive force is small

Read more on deuterons here: brainly.com/question/15146911

#SPJ4

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A ball is dropped from rest at point O . It passes a window with height 3.8 m in time interval tAB = 0.02 s.Identify the correct
Taya2010 [7]

Answer:

VB − VA = g tAB   &   (VA + VB)/2 = h / tAB

Explanation:

s = h = Displacement

tAB = t = Time taken

VA = u = Initial velocity

VB = v = Final velocity

a = g = Acceleration due to gravity = 9.8 m/s²

s=ut+\frac{1}{2}at^2\\\Rightarrow u=\frac{s-\frac{1}{2}at^2}{t}\\\Rightarrow u=\frac{3.8-\frac{1}{2}\times 9.8\times 0.02^2}{0.02}\\\Rightarrow u=189.902\ m/s

v=u+at\\\Rightarrow v=189.902+9.8\times 0.02\\\Rightarrow v=190.098\ m/s

\frac{v+u}{2}=\frac{190.098+189.902}{2}=190\ s

\frac{h}{t}=\frac{3.8}{0.02}=190\ s

Hence, the equations VB − VA = g tAB   &   (VA + VB)/2 = h / tAB will be used

3 0
3 years ago
A piston absorbs 25 J of heat from its surroundings while expanding from
Ivahew [28]
  • The work done is -30 J
  • The heat is 25 J

<h3>What is the heat and the work?</h3>

We know that the work done by a gas could be positive or negative same as the heat. If the work done is positive then work is done on the system.

The work done is obtained from;

W = PΔV

W =  1.0 x 105 Pa(0.0006 m³ - 0.0003 m³)

W = 30 J

Given that the gas absorbs heat from the surroundings and the gas is expanding.

  • The work done is -30 J
  • The heat is 25 J

Learn more about work done on a gas:brainly.com/question/12539457

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6 0
2 years ago
What is the weight in Newtons of a ball with a mass of 7.77 kg?
rusak2 [61]

Answer:

76.1N

Explanation:

Given parameters:

Mass of the ball  = 7.77kg

Unknow:

Weight of balloon  = ?

Solution:

Weight is the vertical force applied on a body.

  Weight = mass x acceleration due gravity

So;

  Weight  = mass x acceleration due to gravity

So;

 Weight  = 7.77 x 9.8  = 76.1N

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3 years ago
To distinguish between properties of the two major types of supernovae: massive star supernovae and white dwarf supernovae. all
const2013 [10]
<span>In my opinion, I myself believe that there are only two supernovae. The first is the white dwarf. It makes sense because if something is too big for its size, it will "explode". Just like a basketball with too much air. Massive star supernovae is like something has reached it's full potential and cannot get any bigger or better.</span>
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3 years ago
Solution A has a specific heat of 2.0 J/g◦C. Solution B has a specific heat of 3.8 J/g◦C. If equal masses of both solutions start
fgiga [73]

Answer: 2. Solution A attains a higher temperature.

Explanation: Specific heat simply means, that amount of heat which is when supplied to a unit mass of a substance will raise its temperature by 1°C.

In the given situation we have equal masses of two solutions A & B, out of which A has lower specific heat which means that a unit mass of solution A requires lesser energy to raise its temperature by 1°C than the solution B.

Since, the masses of both the solutions are same and equal heat is supplied to both, the proportional condition will follow.

<em>We have a formula for such condition,</em>

Q=m.c.\Delta T.....................................(1)

where:

  • \Delta T= temperature difference
  • Q= heat energy
  • m= mass of the body
  • c= specific heat of the body

<u>Proving mathematically:</u>

<em>According to the given conditions</em>

  • we have equal masses of two solutions A & B, i.e. m_A=m_B
  • equal heat is supplied to both the solutions, i.e. Q_A=Q_B
  • specific heat of solution A, c_{A}=2.0 J.g^{-1} .\degree C^{-1}
  • specific heat of solution B, c_{B}=3.8 J.g^{-1} .\degree C^{-1}
  • \Delta T_A & \Delta T_B are the change in temperatures of the respective solutions.

Now, putting the above values

Q_A=Q_B

m_A.c_A. \Delta T_A=m_B.c_B . \Delta T_B\\\\2.0\times \Delta T_A=3.8 \times \Delta T_B\\\\ \Delta T_A=\frac{3.8}{2.0}\times \Delta T_B\\\\\\\frac{\Delta T_{A}}{\Delta T_{B}} = \frac{3.8}{2.0}>1

Which proves that solution A attains a higher temperature than solution B.

7 0
3 years ago
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