Two resistors A and B are arranged in series in one branch of a parallel arrangement. The other branch contains a single resisto
r, C. This parallel arrangement is in series with a single resistor D. Describe how you would find the equivalent resistance of the group.
1 answer:
Answer:
Explanation:
A and B are in series , Total resistance = Ra + Rb
This resistance is in parallel with single resistor C
Equivalent resistance Re = Rc x ( Ra + Rb ) / [Rc + ( Ra + Rb )]
Now this combination is in series in single resistance D .
Total resistance = Rd + Re
= Rd + { Rc x ( Ra + Rb ) / [Rc + ( Ra + Rb )] }
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