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Stella [2.4K]
3 years ago
5

If I accidentally touch a stove and burn myself, which type of heat transfer is occurring?

Physics
1 answer:
allochka39001 [22]3 years ago
5 0

Answer:

radiation is the correct answer

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A car slows from 27 m/s to 5 m/s with a constant acceleration for 6.87 s. What is the car’s acceleration?
Kobotan [32]

In this case, the movement is uniformly delayed (the final rapidity is less than the initial rapidity), therefore, the value of the acceleration will be negative.

1. The following equation is used:

a = (Vf-Vo)/ t

a: acceleration (m/s2)

Vf: final rapidity (m/s)

Vo: initial rapidity (m/s)

t: time (s)

2. Substituting the values in the equation:

a = (5 m/s- 27 m/s)/6.87 s

3. The car's acceleration is:

a= -3.20 m/ s<span>^2</span>

5 0
3 years ago
Which kinds of objects emit visible light in the electromagnetic spectrum?
Triss [41]

Answer : Relatively hot objects

Explanation : We know that, the temperature of the objects is inversely proportional to their wavelengths. The objects emitting radiation in the visible region have short wavelength and hence are relatively hotter.

We know the range of wavelength of the visible spectrum is from 400 nm to 780 nm.





3 0
3 years ago
Read 2 more answers
% of 50 shirts is 35 shirts<br> Your answer math
saul85 [17]

Answer:

70%

Explanation:

35 is 70% of 50, have a good day :)

7 0
3 years ago
A 4 kg block slides down a rough inclined plane inclined at 30° 179009.GIF with the horizontal. Determine the coefficient of kin
mrs_skeptik [129]
F=ma
F= 4x1.2
F= 4.8 N

F= 4gsin30 - Friction
Friction= 19.6 - 4.8 N
Friction= 14.8 N

Friction= u x 4gcos30
14.8 / 4gcos30 = u
u= 0.43596...
u= 0.44

coefficient is 0.44
5 0
3 years ago
When two point charges are a distance d part, the electric force that each one feels from the other has magnitude F. In order to
Serjik [45]

Answer:

E) d/sqrt2

Explanation:

The initial electric force between the two charge is given by:

F=k\frac{q_1 q_2}{d^2}

where

k is the Coulomb's constant

q1, q2 are the two charges

d is the separation between the two charges

We can also rewrite it as

d=\sqrt{k\frac{q_1 q_2}{F}}

So if we want to make the force F twice as strong,

F' = 2F

the new distance between the charges would be

d'=\sqrt{k\frac{q_1 q_2}{(2F)}}=\frac{1}{\sqrt{2}}\sqrt{k\frac{q_1 q_2}{(2F)}}=\frac{d}{\sqrt{2}}

so the correct option is E.

8 0
3 years ago
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