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puteri [66]
1 year ago
8

2-ButeneHC = HCH₃) is a starting material in the manufacture of lubricating oils and many other compounds. Draw two different st

ructures for 2-butene, indicating the s and p bonds in each.
Chemistry
1 answer:
kumpel [21]1 year ago
7 0

But-2-ene is an acyclic alkene with four carbon atoms. It is the simplest alkene exhibiting cis/trans-isomerism; that is, it exists as two geometric isomers cis-but-2-ene and trans-but-2-ene.

It is a petrochemical, produced by the catalytic cracking of crude oil or the dimerization of ethylene.

<h3>What are the isomers of 2-butene?</h3>

Isomeric forms are 1-butene, cis-2-butene, trans-2-butene, and isobutylene.

<h3>Is but-2-ene and 2-butene same?</h3>

The key difference between 1 butene and 2 butene is that 1-butene has a double bond between carbon atoms at the end of the carbon chain, whereas 2-butene has a double bond between carbon atoms at the middle of the compound.

Learn more about 2-butene here:

<h3>brainly.com/question/22818826</h3><h3 /><h3>#SPJ4</h3>
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What substances make up water?
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A water molecule consists of three atoms; an oxygen atom and two hydrogen atoms, which are bond together like little magnets.


An iron pot is made up of only one substance, iron. Iron is an element classified as a transition metal


Iron. Elementsare pure substances that are made up of one kind of atom. Pizza is not an element because it is a mixture of many substances. Water is a pure substance, but it contains two kindsof atom: oxygen and hydrogen.
8 0
3 years ago
Read 2 more answers
1. A dry, empty bottle is placed in an ice bath. After the air inside the bottle is cooled off, a balloon is placed
Alex777 [14]

Answer:

hot air rises and expanded the balloon

Explanation:

thats it.

8 0
3 years ago
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3. If you start with 8x1025 molecules of Cl, and 25 grams of KI, how many grams of KCl would
miskamm [114]

Answer:

Percent yield = 89.1%

Explanation:

Based on the equation:

Cl₂ + 2KI → 2KCl + I₂

<em>1 mole of Cl₂ reacts with 2 moles of KI to produce to moles of KCl</em>

<em />

To solve this quesiton we must find the moles of each reactant in order to find the limiting reactant. With the limiting reactant we can find the moles of KCl and the mass:

<em>Moles Cl₂:</em>

8x10²⁵ molecules * (1mol / 6.022x10²³ molecules) = 133 moles

<em>Moles KI -Molar mass: 166.0028g/mol-</em>

25g * (1mol / 166.0028g) = 0.15 moles

Here, clarely, the KI is the limiting reactant

As 2 moles of KI produce 2 moles of KCl, the moles of KCl produced are 0.15 moles. The theoretical mass is:

0.15 moles * (74.5513g / mol) =

11.2g KCl

Percent yield is: Actual yield (10.0g) / Theoretical yield (11.2g) * 100

<h3>Percent yield = 89.1%</h3>
3 0
3 years ago
Silver occurs in trace amounts in some ores of lead, and lead can displace silver from solution: Pb(s) + 2Ag+ (aq) LaTeX: \longr
VikaD [51]

Answer : The value of \Delta G^o and K is, -180 kJ/mol and 3.6\times 10^{31}

Explanation :

The balanced cell reaction will be,

Pb(s)+2Ag^+(aq)\rightarrow Pb^{2+}(aq)+2Ag(g)

The half-cell reactions are:

Oxidation reaction (anode) : Pb(s)\rightarrow Pb^{2+}(aq)+2e^-

Reduction reaction (cathode) : 2Ag^+(aq)+2e^-\rightarrow 2Ag(g)

Relationship between standard Gibbs free energy and standard electrode potential follows:

\Delta G^o=-nFE^o_{cell}

where,

\Delta G^o = standard Gibbs free energy

F = Faraday constant = 96500 C

n = number of electrons in oxidation-reduction reaction = 2

E^o_{cell} = standard electrode potential of the cell = 0.93 V

Now put all the given values in the above formula, we get:

\Delta G^o=-2\times 96500\times 0.93

\Delta G^o=-179490J/mol=-179.49kJ/mol\approx -180kJ/mol

Now we have to calculate the value of 'K'.

\Delta G^o=-RT\ln K

where,

\Delta G_^o =  standard Gibbs free energy  = -180 kJ/mol

R = gas constant = 8.314\times 10^{-3}kJ/mole.K

T = temperature = 298 K

K = equilibrium constant = ?

Now put all the given values in the above formula 1, we get:

-180kJ/mol=-(8.314\times 10^{-3}kJ/mole.K)\times (298K)\times \ln K

K=3.6\times 10^{31}

Therefore, the value of \Delta G^o and K is, -180 kJ/mol and 3.6\times 10^{31}

5 0
3 years ago
Which statement describes a property that is unique to metalloids?
hodyreva [135]

Answer:

Metalloids are semiconductive.

Explanation:

8 0
3 years ago
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