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Zina [86]
3 years ago
12

You wish to make a 0.435 M perchloric acid solution from a stock solution of 3.00 M perchloric acid. How much concentrated acid

must you add to obtain a total volume of 150 mL of the dilute solution?
Chemistry
1 answer:
lidiya [134]3 years ago
3 0

Answer:

The answer to your question is 21.75 mL of stock solution of [HClO₄]

Explanation:

Data

[HClO₄] = 0.435 M

Stock solution [HClO₄] = 3 M

Total volume = 150 mL

Formula

 Concentration 1 x Volume 1 = Concentration 2 x Volume 2

- Solve for Volume 1

                Volume 1 = Concentration 2 x Volume 2 / Concentration 1

- Substitution

                Volume 1 = 0.435 x 150 / 3

- Simplification

                Volume 1 = 65.25 / 3

- Result

                Volume 1 = 21.75 mL

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Which of the following statements about equilibrium of chemical reactions is correct? See Concept 8.2 (Page 147) View Available
dmitriy555 [2]

Answer:

A reaction that is at equilibrium is not capable of doing any work

Explanation:

Chemical equilibrium is the state of a reversible reaction where the rate of the forward reaction equals the rate of the reverse reaction. While a reaction is in equilibrium the concentration of the reactants and products are constant.

Chemical equilibrium, a condition in the course of a reversible chemical reaction in which no net change in the amounts of reactants and products occurs. A reversible chemical reaction is one in which the products, as soon as they are formed, react to produce the original reactants. At equilibrium, the two opposing reactions go on at equal rates, or velocities, hence there is no net change in the amounts of substances involved. At this point the reaction may be considered to be completed; i.e., for some specified reaction condition, the maximum conversion of reactants to products has been attained.

3 0
3 years ago
In calculating the equilibrium constant for a reaction, the coefficients of the chemical equation are used as exponents for the
BartSMP [9]

Answer: The given statement is TRUE.

Explanation:

An equilibrium reaction is one in which rate of forward reaction is equal to the rate of backward reaction.

Equilibrium constant is defined as the ratio of the product of the concentration of products to the product of the concentration of reactants each raised to their stochiometric coefficient.

For example for the given equilibrium reaction;

2H_2O(g)\leftrightharpoons 2H_2(g)+O_2(g)

K_{eq}=\frac{[H_2]^2[O_2]}{[H_2O]^2}

Thus the given statement that in calculating the equilibrium constant for a reaction, the coefficients of the chemical equation are used as exponents for the factors in the equilibrium expression is True.

7 0
3 years ago
What is the formula for Dicarbon trioxide
Veronika [31]

Answer:

diboron trioxide Formula: B 2 O 3 Molecular weight: 69.620 CAS Registry Number: 1303-86-2

Explanation:

<h3><u><em>hope that helps you</em></u>╰(*°▽°*)╯</h3>
4 0
2 years ago
The combustion of propane may be described by the chemical equation C 3 H 8 ( g ) + 5 O 2 ( g ) ⟶ 3 CO 2 ( g ) + 4 H 2 O ( g ) C
Kipish [7]

Answer: 72 grams of O_2(g) are needed to completely burn 19.7 g C_3H_8(g)

Explanation:

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To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Putting in the values we get:

\text{Number of moles}=\frac{19.7g}{44g/mol}=0.45moles

C_3H_8(g)+5O_2(g)\rightarrow 3CO_2(g)+4H_2O(g)

According to stoichiometry:

1 mole of C_3H_8 requires 5 moles of oxygen

0.45 moles of C_3H_8 require= \frac{5}{1}\times 0.45=2.25 moles of oxygen

Mass of O_2=moles\times {\text {Molar mass}}=2.25\times 32=72g

72 grams of O_2(g) are needed to completely burn 19.7 g C_3H_8(g)

7 0
3 years ago
Trans fats: Think about how the prefix trans- is used in naming alkenes.
wel
In an alkene, cis and trans isomers are possible because the double band is rigid, cannot rotate, has groups attached to the carbons of the double bond that are fixed relative to each other, and only occurs with double bonds-possibility that molecule will have different geometries; two different molecules with slightly different properties. 
-Trans-2 ends of chain across the double bond.
While naming Cis-Trans isomers the prefix cis or trans are placed in front of the alkene name when there are cis-trans isomers. 
4 0
2 years ago
Read 2 more answers
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