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Zina [86]
3 years ago
12

You wish to make a 0.435 M perchloric acid solution from a stock solution of 3.00 M perchloric acid. How much concentrated acid

must you add to obtain a total volume of 150 mL of the dilute solution?
Chemistry
1 answer:
lidiya [134]3 years ago
3 0

Answer:

The answer to your question is 21.75 mL of stock solution of [HClO₄]

Explanation:

Data

[HClO₄] = 0.435 M

Stock solution [HClO₄] = 3 M

Total volume = 150 mL

Formula

 Concentration 1 x Volume 1 = Concentration 2 x Volume 2

- Solve for Volume 1

                Volume 1 = Concentration 2 x Volume 2 / Concentration 1

- Substitution

                Volume 1 = 0.435 x 150 / 3

- Simplification

                Volume 1 = 65.25 / 3

- Result

                Volume 1 = 21.75 mL

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A drop of water with a mass of 0.48 g is vaporized at 100 ∘C and condenses on the surface of a 55- g block of aluminum that is i
bagirrra123 [75]

The final temperature in Celsius of the metal block is 49°C.

<h3>How to find the number of moles ?</h3>

Moles water = \frac{\text{Given mass}}{\text{Molar Mass}}

                     = \frac{0.48\ g}{18\ \text{g/mol}}

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A. Describe the molecule chlorine dioxide, CIO in terms of three possible resonance structures.
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Answer:

See explanation

Explanation:

The compound ClO2 has 19 valence electrons.  ClO2 is a bent molecule with tetrahedral electron pair geometry but has two  lone pairs of electrons. This is indicated by the presence of four electron pairs on the outermost shell of the central atom.

The molecule has an odd number of valence electrons, hence, it is generally regarded as a paramagnetic radical. None of the proposed Lewis structures for the molecule is satisfactory because none of them obeys the octet rule.

From the images attached, one can easily see that the electron dots around the oxygen and chlorine atoms does not satisfy the octet rule in all the resonance structures shown.

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