The actual number of atoms of each element present in the molecule of the compound is represented by the formula known as molecular formula.
Molar mass of the unknown compound = 223.94 g/mol (given)
Mass of each element present in the unknown compound is determined as:
- Mass of carbon,
:
- Mass of hydrogen,
:
- Mass of chlorine,
:
Now, the number of each element in the unknown compound is determined by the formula:
- Number of moles of :
- Number of moles of :
- Number of moles of
Dividing each mole with the smallest number of mole, to determine the empirical formula:
Multiplying with 2 to convert the numbers in formula into a whole number:
So, the empirical formula is 
.
Empirical mass = 
In order to determine the molecular formula:
n = 
n = 
So, the molecular formula is:
Answer:
C). The Bohr-Rutherford model
Explanation:
The 'Bohr-Rutherford model' of the atom failed to elaborate on the attraction between some substances. It essentially targeted hydrogen atoms and failed to explain its stability across multi-electrons. The nature and processes of the chemical reactions remained unillustrated and thus, this is the key drawback of this model. Thus, <u>option C</u> is the correct answer.
Answer:
exothermic entropy is increased
Explanation:
An exothermic process is one whose rate increases when the temperature is decreased. Hence if a decrease in temperature favours the dissolution of more solute at equilibrium, then the process is exothermic.
Similarly, the dissolution of a solute in a solvent increases the disorderliness (entropy) of the system because of the increase in the number of particles present. Hence once a solute in dissolved, the entropy of the system increases.
Answer:
8.5gm O2 produced
Explanation:
When heated, KClO3 decomposes into KCl and O2. 2KClO3⟶2KCl+3O2 If this reaction produced 13.2 g KCl, how many grams of O2 were produced?
for every 2 moles of KCl produced, 3 moles of O2 are produced
Mol weight of KCl =39+35.5=74.5gm
13.2 gm KCl = 13.2/74.5 = 0.177 moles
this will make (3/2) X 0.177 = 0.2655 moles of O2
O2 mol wt is 32 0.2655 X32 = 8.5gm O2 produced
