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Zina [86]
3 years ago
12

You wish to make a 0.435 M perchloric acid solution from a stock solution of 3.00 M perchloric acid. How much concentrated acid

must you add to obtain a total volume of 150 mL of the dilute solution?
Chemistry
1 answer:
lidiya [134]3 years ago
3 0

Answer:

The answer to your question is 21.75 mL of stock solution of [HClO₄]

Explanation:

Data

[HClO₄] = 0.435 M

Stock solution [HClO₄] = 3 M

Total volume = 150 mL

Formula

 Concentration 1 x Volume 1 = Concentration 2 x Volume 2

- Solve for Volume 1

                Volume 1 = Concentration 2 x Volume 2 / Concentration 1

- Substitution

                Volume 1 = 0.435 x 150 / 3

- Simplification

                Volume 1 = 65.25 / 3

- Result

                Volume 1 = 21.75 mL

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Which of these statements is NOT TRUE? Scientists propose explanations that can be explained by examining evidence. Scientists p
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Answer:

The correct option is;

Scientist propose explanations that can be explained by examining evidence

Explanation:

A scientists makes an hypotheses based on possible natural processes to explain the origin and/or the nature of the characteristics of a natural observation. The scientist then source more data and information to put their hypotheses to test. Due to the fact that an hypotheses is based on observable  processes and/or mechanisms, the given hypotheses can be further tested by other scientists through the use of their individually sourced data. From the result of the assessment, the hypotheses can be either accepted or rejected to enable the better clarification of the hypotheses when accepted or the development of a new hypotheses when rejected.

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a solution with a transmittance of 0.44 is analyzed in a spectrophotometer with 6% stray light. calculate the absorbance reporte
IgorLugansk [536]

The absorbance reported by the defective instrument was 0.3933.

Absorbance A = - log₁₀ T

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Tm = 0.44

Absorbance reported in this equipment = -log₁₀ (0.44) = 0.35654

True absorbance can be calculated by true transmittance, Tm = T+S(α-T)

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α= 1, ideal case

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Tm = T+S(α-T)

now, T= Tm-S/ 1-S = 0.44-0.06/ 1-0.06 = 0.404233

therefore, actual reading measured is A = -log₁₀ T = -log₁₀ (0.404233)

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To know more about transmittance click here:

brainly.com/question/17088180

#SPJ4

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