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3 years ago

Name and describe three of the five branches of chemistry.

2 answers:

7 0

Organic Chemistry- Substances only found in living organisms.

Physical Chemistry- Structure of physical compounds and the amount of energy they have.

Inorganic Chemistry- Study of carbon containing compounds.

Minchanka [31]3 years ago

3 0

The five branches of chemistry:
Organic Chemistry, Inorganic Chemistry, Analytical Chemistry, Physical Chemistry, Biochemistry.

(I know <span>Amra111 already answered, I just thought you would want to know the rest.)</span>

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A neutral solution has a(n) _______ amount of hydroxide ions compared to hydrogen ions.

erastovalidia [21]

The answer is 'equal'. Hydroxide ions are OH- and Hydrogen ions are H+. Have you noticed they're opposite charges? Positive + negative = neutral. That's all there is to it :)

4 0

3 years ago

Enter the net ionic equation for this reaction. Express your answer as a net ionic equation. Identify all of the phases in your

Lisa [10]

Answer:

2H+(aq) + 2OH-(aq) → 2H2O(l)

Explanation:

Step 1: The balanced equation

2HCl(aq)+Ca(OH)2(aq) → 2H2O(l)+CaCl2(aq)

This equation is balanced, we do not have the change any coefficients.

Step 2: The netionic equation

The net ionic equation, for which spectator ions are omitted - remember that spectator ions are those ions located on both sides of the equation - will.

2H+(aq) + 2Cl-(aq) + Ca^2+(aq) + 2OH-(aq) → 2H2O(l) + Ca^2+(aq) + 2Cl-(aq)

After canceling those spectator ions in both side, look like this:

2H+(aq) + 2OH-(aq) → 2H2O(l)

6 0

3 years ago

has a standard free‑energy change of − 3.59 kJ / mol at 25 °C. What are the concentrations of A , B , and C at equilibrium if, a

Mamont248 [21]

Answer: The concentrations of A , B , and C at equilibrium are 0.1583 M, 0.2583 M, and 0.1417 M.

Explanation:

The reaction equation is as follows.

$A + B \rightarrow C$

Initial : 0.3 0.4 0

Change: -x -x x

Equilbm: (0.3 - x) (0.4 - x) x

We know that, relation between standard free energy and equilibrium constant is as follows.

$\Delta G = -RT ln K$

Putting the given values into the above formula as follows.

$\Delta G = -RT ln K$

$-3.59 kJ/mol = -8.314 \times 10^{-3} kJ/mol K ln (\frac{x}{(0.3 - x)(0.4 - x)})$

x = 0.1417

Hence, at equilibrium

[A] = 0.3 - 0.1417

= 0.1583 M

[B] = 0.4 - 0.1417

= 0.2583 M

[C] = 0.1417 M

5 0

3 years ago

1. What is the relation between distance and speed?

Inga [223]

Answer:

option no b is right answer

6 0

3 years ago

Need help plz help any one

dimulka [17.4K]

Hi!

Composition: the way in which a whole is made up

Hope I helped!
Have a nice day!

6 0

3 years ago