Volume of the box observed at the given speed is 7.89 m³
Given:
Length of side of box = 1.5 m
horizontal speed = 0.90 c
To Find:
Volume of box
Solution: The amount of space occupied by a three-dimensional figure as measured in cubic units (as inches, quarts, or centimeters)
The edge length of the cube according to the stationary observer is calculated as
a' = a x √ 1 - v^2/c^2
a' = 1.5 x √ 1 - (0.9c)^2/c^2
a' = 1.5 x 0.19
a' = 0.285 m
The volume of the cube is calculated as follows;
V = A x a'
V = (a)^2 x a'
V = (1.5)^2 x 0.285
V = 7.89 m³
Thus, the volume of the box observed at the given speed is 7.89 m³
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Kinematic equations
v=at. v=9.81x3.2 v=32m/s (approx)
v^2=2axheight.
32x32/2x10=height
16x32/10 = height
height is approx 48metres
Answer:
2.4 kg
1 kg = 10N
2.4 kg = ?
2.4 kg = 24N
On the moon 1/6th
1/6 * 24 = 4N
therefore weight of the textbook on the moon would be 4N
Answer:
0.784 m
Explanation:
The motion of the ball is a projectile motion, which consists of two independent motions:
- a horizontal uniform motion, with constant speed of 
- a vertical accelerated motion, with constant acceleration 
towards the ground and initial position 
By looking at the vertical motion, we can find the time t at which the ball hits the ground, which is the time t at which the vertical position y becomes zero:
And now we can use the horizontal motion to find the total horizontal distance traveled during this time interval:
