Answer:
The minimum wall thickness required for the spherical tank is 0.0189 m
Explanation:
Given data:
d = inside diameter = 8.1 m
P = internal pressure = 1.26 MPa
σ = 270 MPa
factor of safety = 2
Question: Determine the minimum wall thickness required for the spherical tank, tmin = ?
The allow factor of safety:
The minimun wall thickness:
In order to make his measurements for determining the Earth-Sun distance, Aristarchus waited for the Moon's phase to be exactly half full while the Sun was still visible in the sky. For this reason, he chose the time of a half (quarter) moon.
<h3 /><h3>How did Aristarchus calculate the distance to the Sun?</h3>
It was now possible for another Greek astronomer, Aristarchus, to attempt to determine the Earth's distance from the Sun after learning the distance to the Moon. Aristarchus discovered that the Moon, the Earth, and the Sun formed a right triangle when they were all equally illuminated. Now that he was aware of the distance between the Earth and the Moon, all he needed to know to calculate the Sun's distance was the current angle between the Moon and the Sun. It was a wonderful argument that was weakened by scant evidence. Aristarchus calculated this angle to be 87 degrees using only his eyes, which was not far off from the actual number of 89.83 degrees. But when there are significant distances involved, even slight inaccuracies might suddenly become significant. His outcome was more than a thousand times off.
To know more about how Aristarchus calculate the distance to the Sun, visit:
brainly.com/question/26241069
#SPJ4
Answer:
none of the above
Explanation:
The actual answer is '91 protons'. In fact, the beta decay of the thorium-234 is the following:
where inside the nucleus of Thorium (90 protons), a neutron turns into an electron (the beta particle) + a proton. Therefore, the resulting nucleus (which is Protoactinium) has a total of 90+1 = 91 protons.
So, the correct answer would be '91 protons'.
There are two ways to solve this problem. First we write the given.
Given: Force F = 400 N; Height h = 0.5 m; Time t = 2 s
Formula: P = W/t; but Work W = Force x distance or W = f x d
Weight is also a Force, therefore: W = mg, solve for Mass m = ?
m = w/g m = 400 N/9.8 m/s² m = 40.82 Kg
P = W/t = F x d/t = mgh/t P = (40.82 Kg)(9.8 m/s²)/2 s
P = 100 J/s or 100 Watts
Answer:
0.532
Explanation:
Your equation to find the second bright interference maximum is gonna be this: d sin (Θ) = m λ
First, find your variables.
λ = 580 · 10^-9
d = 0.000125
m = 2
Next, fill in the equation.
d sin (θ) = m λ
(0.000125) sin (θ) = (2) (580·10^-9)
Then isolate your variable.
θ = arcsin ( (2)(580·10^-9) / (0.000125) )
Run your equation and you will end up with 0.53171246 , which rounds to 0.532.
The main thing you have to watch out for is make sure you are calculating for the bright interference and not the dark interference, as well as checking you're calculating for the maximum, not the minimum.
I hope this helps :D
