Question 10 of 15<br> If the period of a wave increases, its frequency must blank

The kinetic energy of any moving object is

K.E. = (1/2) (mass) (speed)² .

To use this simple formula, the 'mass' has to be in kilograms,
and the 'speed' has to be in meters-per-second.

You can see that we have a slight problem that has to be cleaned up:
The speed in the question is given in "kilometers per hour", but we'll
need it in "meters per second". So let's convert that right now:

(600 km/hour) x (1 hour / 3600 seconds) x (1000 meters / km)

= (600 x 1 x 1000 / 3600) (km-hour-meters / hour-second-km)

= 166.67 meters/second .

Now we're ready to plug numbers into the formula for K.E.

(1/2) (mass) (speed)²

= (1/2) (80,000 kg) (166.67 m/s)²

= (40,000 kg) (27,777.8 m²/s²)

= 1,111,111,111 kg-m²/s²

= 1.1... x 10⁹ Joules (choice D)

8 0

3 years ago

Explain how all the organelles in a cell model work together to provide nutrition and energy for the cell.

slega [8]

These organelles are like the organs in a human and they help the cell stay alive. Each organelle has it's own specific function to help the cell survive. The nucleus of a eukaryotic cell directs the cell's activities and stores DNA. Eukaryotes also have a golgi apparatus that packages and distributes proteins.

6 0

3 years ago

A bowling ball is far from uniform. Lightweight bowling balls are made of a relatively low-density core surrounded by a thin she

tester [92]

Answer:

a) I = 1,75 10-² kg m² and b) I = 1.49 10⁻² kg m²

Explanation:

The expression for the moment of inertia is

I = ∫ r² dm

The moment of inertia is a scalar by which an additive magnitude, we can add the moments of inertia of each part of the system, taking into account the axis of rotation.

I = I core + I shell

The moment of inertia of a solid sphere is

I sphere = 2/5 MR²

The moment of inertia of a thin spherical shell is

I shell = 2/3 M R²

a) Let's apply to our system, first to the core of weight 1.6 kg and diameter 0.196m, the radius is half the diameter

R = d / 2

R= 0.196 m / 2 = 0.098 m

I core = 2/5 1.6 0.098²

I core = 6.147 10-3 kg m²

Let's calculate the moment of inertia of the shell of mass 1.6 kg with a diameter of 0.206 m

R = 0.206 / 2

R = 0.103 m

I shell = 2/3 1.6 0.103²

I shell = 1,132 10-2 kg m²

The moment of inertia of the ball is the sum of these moments of inertia,

I = I core + I shell

I = 6,147 10⁻³ + 1,132 10⁻² = 6,147 10⁻³ + 11.32 10⁻³

I = 17.47 10⁻³ kg m²

I = 1,747 10-² kg m²

b) Now the ball is report with mass 3.2kg and diameter 0.216 m

R = 0.216 / 2

R = 0.108 m

It is a uniform sphere

I = 2/5 M R²

I = 2/5 3.2 0.108²

I = 1.49 10⁻² kg m²

7 0

3 years ago

Question 10 of 15 If the period of a wave increases, its frequency must blank