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mariarad [96]
3 years ago
13

For protection hermit crabs use gastropod shells to hide their bodies so only their heads are visible. Students research why the

population of hermit crabs has been decreasing. One question hey should ask is-
Physics
1 answer:
KatRina [158]3 years ago
3 0

Answer:

Due to suffocation and toxic paint.

Explanation:

The population of hermit crabs has been decreasing because of suffocation and poison. Many crabs actually die slowly from suffocation because their gills require high humidity in order to breathe properly. Hermit crabs are slowly poisoned by tap water in which the toxic substances present in the paint that dissolves their shells that leads to the death of hermit crabs.

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you are the person in charge of building a nuclear power plant in florida. your first choice is to select a
sammy [17]

Answer: you are the person in charge of building a nuclear power plant in Florida. your first choice is to select a site for building the power plant.

Explanation: To find the answer, we need to know more about the nuclear power plants and the criteria to select the site for power plant.

<h3>What you mean by nuclear power plants?</h3>
  • Nuclear power can be defined from the nuclear fission reaction.
  • These power plants will heat the water to produce steam and this steam is used to spin large turbines and thus generates electricity.
<h3>How to select the site for nuclear power plant?</h3>
  • We have to consider the following things,
  • keep distance from populated area.
  • distance from load center.
  • Accessibility to site.
  • Water availability and fuel availability.
  • waste disposal.

Thus, we can conclude that, before building a nuclear power plant, our first choice should be to select a site.

Learn more about the nuclear power plants and the criteria to select the site for power plant here:

brainly.com/question/28045272

#SPJ4

8 0
2 years ago
Rusty Pickins, a gold miner, has just found a chunk of gold. Rusty would like to change the gold from a solid to a liquid, so th
Vitek1552 [10]
<span>b.) Add heat to increase the molecular motion of the atoms</span>
5 0
4 years ago
At which point is the kinetic energy the greatest?
pshichka [43]

Answer:

X

Explanation:

ur welcome

6 0
4 years ago
Calculate the freezing point of a solution of 40.0 g methyl salicylate, c7h6o2, dissolved in 800. g of benzene, c6h6. and the fr
Cloud [144]
From the problem statement, we are given a solution thus the solute in the solution would have an effect on some of the properties of the whole system. These properties are called the colligative properties. To calculate the freezing point of the solution, we use the freezing point depression equation which is expressed as follows:

ΔTf = kf(m)i

where ΔTf represents the freezing point depression, kf is a constant which 4.90 C/m for benzene, i is the vant hoff factor which is 1 for the given solute since it does not dissociate into ions and m is the molality of the solution. We calculate as follows:

ΔTf = kf(m)i
ΔTf = 4.90 (40.00 / .800 (122.13)) (1)
ΔTf = 2.01 C

ΔTf = Tf - Tfs
Tfs = 5.5 - 2.01
Tfs = 3.49 C

The correct answer would be the first option.


3 0
3 years ago
A 12.5843-gram sample of metal bromide, MBr4, was dissolved and, after reaction with silver nitrate, AgNO3, all of the bromide w
barxatty [35]

Answer:

zirconium

Explanation:

Given, Mass of AgBr(s) = 23.0052 g

Molar mass of AgBr(s) = 187.77 g/mol

The formula for the calculation of moles is shown below:

Moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles\ of\ AgBr= \frac{23.0052\ g}{187.77\ g/mol}

Moles\ of\ AgBr= 0.1225\ mol

The reaction taking place is:

MBr_4+4AgNO_3\rightarrow 4AgBr+M(NO_3)__4

From the reaction,

4 moles of AgBr is produced when 1 mole of MBr_4 undergoes reaction

1 mole of AgBr is produced when 1 / 4 mole of MBr_4 undergoes reaction

0.1225 mole of AgBr is produced when \frac {1}{4}\times 0.1225 mole of MBr_4 undergoes reaction

Moles of MBr_4 got reacted = 0.030625 moles

Mass of the sample taken = 12.5843 g

Let the molar mass of the metal = x g/mol

So, Molar mass of MBr_4 = x + 4 × 79.904 g/mol = 319.616 + x g/mol

Thus,

0.030625 = \frac{12.5843}{319.616 + x}

Solve for x,

we get, x = 91.2999 g/mol

<u>The metal shows +4 oxidation state and has mass of 91.2999 g/mol . The metals is zirconium.</u>

8 0
3 years ago
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