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3 years ago

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Physics

1 answer:

grin007 [14]3 years ago

6 0

Answer:

You have to Find x, y, and z such that x³+y³+z³=k, for each k from 1 to 100.

Explanation: And here's the answer in Binary for some fun: 01000110 01101001 01101110 01100100 00100000 01111000 00101100 00100000 01111001 00101100 00100000 01100001 01101110 01100100 00100000 01111010 00100000 01110011 01110101 01100011 01101000 00100000 01110100 01101000 01100001 01110100 00100000 01111000 11000010 10110011 00101011 01111001 11000010 10110011 00101011 01111010 11000010 10110011 00111101 01101011 00101100 00100000 01100110 01101111 01110010 00100000 01100101 01100001 01100011 01101000 00100000 01101011 00100000 01100110 01110010 01101111 01101101 00100000 00110001 00100000 01110100 01101111 00100000 00110001 00110000 00110000 00101110

Separate Answer: 01001000 01100101 01101100 01101100 01101111 00100000 01110100 01101000 01100101 01110010 01100101

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A perfectly elastic collision occurs between a 15.0-kg mass traveling at 3.50 m/s and a 9.00-kg mass traveling at 2.35 m/s. if t

BaLLatris [955]

Momentum is conserved in a collision. Momentum is mass*velocity, so you can find your answer by calculating initial and final momentums and setting them equal to each other.

15kg * 3.50 m/s + 9kg * 2.35 m/s = 73.65 kg m/s

73.65 = 9 * 2.8 + 15x

solve for x
x= 3.23

The final velocity is 3.23 m/s

5 0

3 years ago

) A 1000 kg car travelling at 50 m/s slams into a 1500 kg parked truck in an inelastic manner as

solmaris [256]

(a)

KE = m v^2 / 2 = (1200 kg)(20 m/s)^2 / 2 = 240,000 J

(b)

The energy is entirely dissipated by the force of friction in the brake system.

(c)

W = delta KE = KEf - KEi = (0 - 240,000) J = -240,000 J

(d)

Fd = delta KE

F = (delta KE) / d = (-240,000 J) / (50 m) = -4800 N

The magnitude of the friction force is 4800 N.

8 0

4 years ago

Simplified. The absorption spectra of ions have been used to identify the presence of the elements in the atmospheres of the sun

Nookie1986 [14]

Answer:

The answer is " $3.83 \times 10^9 \ m$ "

Explanation:

Z=2, so the equation is $E= \frac{-4B}{n^2}$

Calculate the value for E when:

n=2 and n=9

The energy is the difference in transformation, name the energy delta E Deduct these two energies

In this transition, the wavelength of the photon emitted is:

$\Delta E=2.18 \times 10^{-18} ( \frac{1}{4}- \frac{1}{81})$

$\lambda = \frac{h c}{\Delta E}$

$h ( Planck's\ constant) = 6.62 \times 10^{(-34)} \ Js \\\\ speed \ of \ light = 3 \times 10^{8} \ \frac{m}{s}\\\\= \frac{6.62 \times 10^{(-34)} \times 3 \times 10^ {8}}{2.18 \times 10^{-18}} (\frac{1}{4}- \frac{1}{81}) \\\\=3.83 \times 10^9 \ m\\\\$

6 0

3 years ago

Somebody please help

suter [353]

Answer:

a = 0.1067 [m/s²]

Explanation:

In order to solve this problem, we must first draw a free body diagram with the forces acting on it.

In the attached image we can find the free body diagram.

The net force can be found by performing a sum of forces on the X-axis, these forces are seen in the free body diagram.

∑Fx = Fr

where:

Fr = resultant force [N] (units of Newtons)

$F_{r}=275+275-310\\F_{r}=240[N]$

Acceleration can be found by means of Newton's second law, which tells us that the sum of the forces in a body or the resulting force is equal to the product of mass by acceleration.

∑F = m*a

where:

m = mass = 2250 [kg]

a = acceleration [m/s²]

$240=2250*a\\a=0.1067[m/s^{2} ]$

5 0

3 years ago

If scientists could bore though Earth's interior, what change would they most likely notice as they passed from the lithosphere

CaHeK987 [17]

Answer:

It gets hotter and hotter and it would start to be a liquid lava

Explanation:

5 0

3 years ago