If an object is in rest it will stay at rest so it will stay put until a force acts upon it
The magnitude of the magnetic field on the axis of the ring 5 cm from its center is 143 pT.
The radius of the nonconducting ring is R = 10 cm.
The ring is uniformly charged q = 10 μC.
The angular speed of the ring, ω = 20 rad/s
The ring is x = 5 cm from the center of the ring.
Now,
R = 10 cm = 0.1 m
q = 10.0 μC = 10 × 10⁻⁶ C
x = 5 cm = 0.05 m
The magnetic field on the axis of a current loop is given as:
B = [ μ₀ IR² ] / [4π(x² + R²)^{3/2} ]
Now, I = q / [2π/ω]
So, the magnitude of the magnetic field which is directed away from the center is:
B = [ μ₀ ωqR² ] / [4π(x² + R²)^{3/2} ]
B = [ μ₀ (200) (10 × 10⁻⁶) (0.1)² ] / [4π((0.05)² + (0.1)²)^{3/2} ]
B = 1.43 × 10⁻¹⁰ T
B = 143 pT
Learn more about the magnetic field here:
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Answers :
Explanation:
Given that.
First cylinder data
Inertial I₁ = 2.4 kgm²
angular speed ω₁ = 5.8 rad/s.
Second cylinder data
inertia I₂ = 1.3 kgm²
angular speed ω₂ = 7.0 rad/s.
If the cylinders couple so they have the same rotational axis, what is the angular speed of the combination (in rad/s)?
So, the cylinder couple and move together with the same angular speed
Then, using conservation of angular momentum
L(final) = L(initial)
(I₁ + I₂) • ω = I₁•ω₁ + I₂ω₂
(2.4+1.3)•ω = 2.4 × 5.8 + 1.3 × 7
3.7•ω = 23.02
ω = 23.02 / 3.7
ω = 6.22 rad/s
The combine angular speed of the cylinder is 6.22 rad/s
Explanation:
The period is the time it takes for the spinner to rotate one revolution, or 2π radians.
T = 2π / ω
T = (2π rad) / (140 rad/s)
T = 0.0449 s
The tangential velocity is the product of the angular velocity and the radius.
v = ωr
v = (140 rad/s) (3.7 cm)
v = 518 cm/s
Answer:
Explained
Explanation:
This happens because the water cancels the focusing effect of our eye lens. A drop of water makes a lens because of the different refractive indices of water and air.
When we are underwater with naked eyes, the front part of our eye lens does not have different refractive indices anymore… both the inside lens and outside lens are essentially water ( lens inside our eyes are water only surrounded by a membrane)… hence, that part of the lens does not focus the light anymore. And thus, your eyes don’t work well anymore. (It can only partly correct for this, by bending the lens more)
When we put swimming goggles on, we remove the water and again have air in front of our eye lenses, and they work normally now. Obviously, we have created an extra interface between water and air in front of our swimming goggles. However, this surface(the goggle) is flat. And thus it does not function as a lens but only as a window.