Answer is: this is synthesis reaction.<span>
</span>Chemical reaction: Ba + F₂ → BaF₂.
Synthesis reaction<span> is a type of reaction in which multiple reactants combine to form a single product.
</span>In barium fluoride, barium has oxidation number +2 and fluorine has oxidation number -1, so compound has neutral charge.
8.38e -21Q^2 -1.07e -23Q^2 +3.15e +19
= 10.46e -44Q^2 + 19
44Q^2 = 10.46e + 19
Q^2 = 523/2200e + 19/44
Q1= ≈ -1.03828
Q2= ≈ 1.03828
Answer:
The concentration of the pyridinium cation at equilibrium is 1.00×10⁻³ M
Explanation:
In water we have
C₅H₅NHBr + H₂O ⇒ C₅H₅NH+ + Br−
Pyridinium Bromide (C₅H₅NHBr) Dissociates Completely Into C₅H₅NH+ And Br− as such it is a strong Electrolyte.
Therefore the number of moles of positive ion produced per mole of C₅H₅NHBr is one
pH = - log [H₃O⁺] Therefore 10^-pH = [H₃O⁺] = concentration of C₅H₅NHBr
= 10⁻³ = 0.001M = concentration of C₅H₅NHBr
The concentration of C₅H₅NHBr is = 1.00×10⁻³ M to two places of decimal
Answer:
collecting relevant data
Explanation:
got this answer from another website ;)
Answer:
pH=1.6
Explanation:
Recall that pH= -log [H+]
Plug the 2.5 x 10^-2 into [H+].
-log (2.5 x 10^2)
=1.6
Hoped this helped!
