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2 years ago

Does a wire connected to a dc source, such as a battery, emit an electromagnetic wave?

Physics

1 answer:

Lina20 [59]2 years ago

7 0

The wire connected to the DC source doesn't emit electromagnetic waves.

The electromagnetic wave is an oscillation of electric fields and magnets field that sustains each other, this wave time has the characteristics that it can travel without a material medium, for which they are of extreme importance.

It is caused by DC sources such as batteries only having a constant voltage, it is different from AC sources which have different voltage over time, AC voltage can induce the wire because AC sources have magnetic flux change. DC sources don't have magnetic flux change so they don't emit electromagnetic waves.

Learn more electromagnetic waves at: brainly.com/question/25847009

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What is population inversion and what is laser inversion?

hoa [83]

Answer:

Population inversion, in physics, the redistribution of atomic energy levels that takes place in a system so that laser action can occur. Although absorption and emission of energy is a continuous process, the statistical distribution (population) of atoms in the various energy states is constant. ...

laser inversion is photon that can stimulate the production of other photons of exactly the same wavelength because of stimulated emission of radiation.

Explanation:

5 0

3 years ago

Describe your motion in terms of velocity and acceleration as you ride in a car down the street, come to a red light, wait for t

aleksandr82 [10.1K]

Ride in a car down the street: constant velocity,
come to a red light: negative acceleration,
wait for the green light: zero velocity,
<span>start off again: </span>positive acceleration

7 0

3 years ago

Read 2 more answers

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madreJ [45]

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3 years ago

A radar station detects an airplane approaching directly from the east. At first observation, the range to the plane is 375.0 m

Gekata [30.6K]

Answer:

819.78 m

Explanation:

<u>Given:</u>

OA = range of initial position of the airplane from the point of observation = 375 m
OB = range of the final position of the airplane from the point of observation = 797 m
$\theta$ = angle of the initial position vector from the observation point = $43^\circ$
$\alpha$ = angle of the final position vector from the observation point = $123^\circ$
$\vec{AB}$ = displacement vector from initial position to the final position

A diagram has been attached with the solution in order to clearly show the position of the plane.

$\vec{OA} = OA\cos \theta \hat{i}+OA \sin \theta \hat{j}\\\Rightarrow \vec{OA} = 375\ m\cos 43^\circ \hat{i}+375\ m\sin 43^\circ \hat{j}\\\Rightarrow \vec{OA} = (274.26\ \hat{i}+255.75\ \hat{j})\ m\\\vec{OB} = OB\cos \alpha \hat{i}+OB \sin \alpha \hat{j}\\\Rightarrow \vec{OB} = 797\ m\cos 123^\circ \hat{i}+797\ m\sin 123^\circ \hat{j}\\\Rightarrow \vec{OB} = (-434.08\ \hat{i}+668.42\ \hat{j})\ m$

Displacement vector of the airplane will be the shortest line joining the initial position of the airplane to the final position of the airplane which is given by:

$\vec{AB}=\vec{OB}-\vec{OA}\\\Rightarrow \vec{AB} = (-434.08\ \hat{i}+668.42\ \hat{j})\ m-(274.26\ \hat{i}+255.75\ \hat{j})\ m\\\Rightarrow \vec{AB} = (-708.34\ \hat{i}+412.67\ \hat{j})\ m$

The magnitude of the displacement vector = $\sqrt{(-708.34)^2+(412.67)^2}\ m = 819.78\ m$

Hence, the magnitude of the displacement of the plane is 819.67 m during the period of observation.

8 0

3 years ago

Copper wire is 1. 9 mm in diameter and carries a current of 20 a. What is the electric field stregnth inside this wire?

Tju [1.3M]

The electric field strength will be 0.6252 V/m. It is the strength at which the field is created by charges.

<h3>What is electric file strength?</h3>

The electric field strength is defined as the ratio of electric force and charge.

The electric field strength is found as;

$\rm E = \frac{I \rho }{A} \\\\ \rm E = \frac{20 \times 1.68 \times 10^{-8} }{ (0.6385 \times 10^{-6}} \\\\ E= 0.5262 \ V/m$

Hence, the electric field strength will be 0.6252 V/m.

To learn more about the electric field strength, refer to the link;

brainly.com/question/4264413

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3 0

2 years ago