<span>the difference of electrical potential between two points. hope this helps</span>
Answer:
∴ fractional compression = 1.34 × 10⁻²
Explanation:
given,
depth of Indian ocean = 3000 m
Bulk modulus of the water = 2.2 x 10⁹ N/m²
We know,
P = P₀ + ρgh
P₀ is the atmospheric pressure
P₀ = 10⁵ N/m²
ρ is the density of the water, 1000 Kg/m³
P = 10⁵ + 1000 × 9.8 × 3000 = 2.94 × 10⁷ N/m²
using formula,
B = P/{-∆V/V}
B is bulk modulus and { -∆V/V} is the fractional compression
∴ fractional compression = 1.34 × 10⁻²
Answer:
a. Your mass with the basketball is 55.5 kg
b. Your new velocity is 0.045 m/s
Explanation:
We first add your weight and the basketballs weight to get 55.5 kg.
Then to find b. we use the equation: v final = (m1 * v1) / (m1 +m2)
So m1 is the basketball which is 0.5 kg and v1 is 5 m/s. So the top half is (0.5 * 5)
The bottom half is just our weights added together.
When the truck's weight is added to the boat, the boat sinks 5 cm deeper,
and displaces additional water whose weight is equal to the weight of the
truck.
The volume of the additional displaced water is
(3.9 m) x (6.3 m) x (5.0 cm)
= (3.9 m) x (6.3 m) x (0.05 m) = 1.2285 m³ .
The weight of that much water is the weight of the truck.
Mass of 1 liter of water = 1 kilogram
1.2285 m³ = 1,228.5 liters = 1,228.5 kg of water.
Weight = (mass) x (gravity)
= (1,228.5 kg) x (9.8 m/s²) = 12,039 Newtons.
(about 2,708 pounds)
