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Sveta_85 [38]
2 years ago
7

Copper wire is 1. 9 mm in diameter and carries a current of 20 a. What is the electric field stregnth inside this wire?

Physics
1 answer:
Tju [1.3M]2 years ago
3 0

The electric field strength will be 0.6252 V/m. It is the strength at which the field is created by charges.

<h3>What is electric file strength?</h3>

The electric field strength is defined as the ratio of electric force and charge.

The electric field strength is found as;

\rm E = \frac{I \rho }{A} \\\\ \rm E = \frac{20  \times 1.68 \times 10^{-8} }{ (0.6385 \times 10^{-6}} \\\\ E= 0.5262 \  V/m

Hence, the electric field strength will be 0.6252 V/m.

To learn more about the electric field strength, refer to the link;

brainly.com/question/4264413

#SPJ4

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A human hair is approximately 56 µm in diameter.
Ann [662]

Answer:

The diameter is 0.000056 m

Explanation:

Lets explain the relation between the meter and the micrometer

1 Meter is equal to 1000000 (one million) micrometers

1 micrometer = \frac{1}{1000000}=\frac{1}{10^{6}}=10^{-6}

The symbol of the meter is m

The symbol of micrometer is μm

A human hair is approximately 56 µm in diameter

We need to express this diameter in meter

To do that we divide this number by 1,000,000 or multiply it by 10^{-6}

→ \frac{56}{1000000}=0.000056  56 µm = 0.000056 m

→ OR

→ 56*10^{-6}=0.000056

→ 56 µm = 0.000056 m

<em>The diameter is 0.000056 m</em>

4 0
3 years ago
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Hoochie [10]

Answer:

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Explanation:

5 0
3 years ago
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a 3000 kg and a 7000 kg Mass attract each other with a force of 0.0015 N. What distance separates the two objects (Radius) (Plea
frutty [35]

Answer:

<h3> 3.057m</h3>

Explanation:

According to law of gravitation;

F = GMm/d²

G is the universal gravitation

M and m are the masses

d is the distance between the masses

d² = GMm/F

d² = 6.67408 × 10-11 *3000*7000/0.0015

d² = 140.15568*10^-5/0.0015

d² = 1.4016*10^-3/0.0015

d² = 1.4016*10^-3/1.5*10^-3

d²  = 0.9344*10

d² = 9.344

d = √9.344

d = 3.057m

Hence the distance between the two objects is  3.057m

3 0
3 years ago
16. Calculate the mass in kg of an object that is being accelerated 12 m/s with a force of 654 N.
Cloud [144]
(654m/s ) / (12m/s) = 54.5 kg.
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3 years ago
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The work function for tungsten metal is 4.52eV a. What is the cutoff (threshold) wavelength for tungsten? b. What is the maximum
Tanya [424]

Answer: a) 274.34 nm; b) 1.74 eV c) 1.74 V

Explanation: In order to solve this problem we have to consider the energy balance for the photoelectric effect on tungsten:

h*ν = Ek+W ; where h is the Planck constant, ek the kinetic energy of electrons and W the work funcion of the metal catode.

In order to calculate the cutoff wavelength we have to consider that Ek=0

in this case  h*ν=W

(h*c)/λ=4.52 eV

λ= (h*c)/4.52 eV

λ= (1240 eV*nm)/(4.52 eV)=274.34 nm

From this h*ν = Ek+W;  we can calculate the kinetic energy for a radiation wavelength of 198 nm

then we have

(h*c)/(λ)-W= Ek

Ek=(1240 eV*nm)/(198 nm)-4.52 eV=1.74 eV

Finally, if we want to stop these electrons we have to applied a stop potental equal to 1.74 V . At this potential the photo-current drop to zero. This potential is lower to the catode, so this  acts to slow down the ejected electrons from the catode.

5 0
3 years ago
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