10. Put the following in order of increasing size:

Physics

1 answer:

Blababa [14]1 year ago

3 0

In the increasing size order, they are Universe, Andromeda galaxy, solar system, Arcturus, Sun, Earth.

The universe, cosmos contains all things. It has countless billions of galaxies.
The Andromeda Galaxy, together with the Triangulum Galaxy and about 30 other smaller galaxies, is the largest galaxy in the Local Group, which also contains the Milky Way.
A solar system comprises a star and all its planets, asteroids, comets, and other celestial bodies. It is considerably bigger in the universe, cosmos than a star.
Arcturus is a huge red star in the Northern Hemisphere of the Earth's atmosphere. When the sun has evolved into a red giant, it will look like Arcturus. Arcturus has a diameter that is roughly 25 times greater than the sun and earth.

Learn more about the universe here:

brainly.com/question/8705671

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A 60kg bicyclist (including the bicycle) is pedaling to the

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a) 4 forces

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c) 246 N

Explanation:

Let's count the forces acting on the bicylist:

1) Weight ( $W=mg$ ): this is the gravitational force exerted on the bicyclist by the Earth, which pulls the bicyclist towards the Earth's centre; so, this force acts downward (m = mass of the bicyclist, g = acceleration due to gravity)

2) Normal reaction (N): this is the reaction force exerted by the road on the bicyclist. This force acts vertically upward, and it balances the weight, so its magnitude is equal to the weight of the bicyclist, and its direction is opposite

3) Applied force ( $F_A$ ): this is the force exerted by the bicylicist to push the bike forward. Its direction is forward

4) Air drag ( $R$ ): this is the force exerted by the air on the bicyclist and resisting the motion of the bike; its direction is opposite to the motion of the bike, so it is in the backward direction

So, we have 4 forces in total.

Here we can find the net force on the bicyclist by using Newton's second law of motion, which states that the net force acting on a body is equal to the product between the mass of the body and its acceleration:

$F_{net}=ma$