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Montano1993 [528]
2 years ago
10

vector ????⃗ has a magnitude of 17.9 and its direction is 80∘ counter‑clockwise from the x- axis. what are the x- and y- compone

nts of the vector?
Physics
1 answer:
Reika [66]2 years ago
5 0

We have vector (17.9*cos80^{0},17.9*sin80^{0})

Therefore,

x component = 17.9 * cos80 degree = 3.108

y component = 17.9 * sin80 degrees = 17.628

<h3>What is a vector?</h3>

An object with both magnitude and direction is referred to be a vector. A vector can be visualized geometrically as a directed line segment, with an arrow pointing in the direction and a length equal to the magnitude of the vector. The vector points in a direction from its tail to its head.

If the magnitude and direction of two vectors match, they are the same vector. This shows that if we move a vector to a different location without rotating it, the final vector will be the same as the initial vector. The vectors that denote force and velocity are two examples. The direction of force and velocity are both fixed. The size of the vector would represent the force's strength or the velocity's corresponding speed.

To know more about vectors, visit:

brainly.com/question/12937011

#SPJ4

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Seismograph is the correct answer

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Answer: the correct option is D (17m).

Explanation: The farthest distance at which a typical "nearsighted" frog can see clearly in air is 17m.

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What is the mass of an object moving with a velocity of 4 m/s and a kinetic energy of 2000 Joules?
ale4655 [162]

Answer:

m = 250 kg

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Hope this helps

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Read 2 more answers
The highest speed attained by a cyclist on level ground is 105 km/h. To attain this speed, the cyclist used a streamlined recumb
omeli [17]

Answer:

The acceleration is 0.133 m/s²

The time taken to build the final speed is 219.32 s

Explanation:

Given;

final speed of the cyclist, v = 105 km/h = 29.17 m/s²

distance traveled by the cyclist, d = 3.2 km = 3,200 m

initial speed, u = 0

Apply the following kinematic equation to determine the acceleration of the cyclist;

v² = u² + 2as

(29.17 )² = 0 + (2 x 3200)a

850.89 = 6400a

a = (850.89 ) / (6400)

a = 0.133 m/s²

The time taken to build up the final speed is given by;

v = u + at

29.17 = 0 + (0.133)t

t = 29.17 / 0.133

t = 219.32 s

4 0
3 years ago
A 60 kg boy and 40 kg girl stand on skateboards on a frictionless horizontal surface. The boy pushes the girl away from him. The
bezimeni [28]

Here in the above situation when boy pushes the girl there will be equal and opposite force on boy as per Newton's III law.

Due to this action reaction law boy will also go back with some speed.

Since there is no external force on this girl + boy system so we can use momentum conservation principle here.

As per momentum conservation

m_1v_{1i} + m_2v_{2i} = m_1v_{1f} + m_2v_{2f}

60*0 + 40*0 = 60*v_{1f} + 40*0.3

0 = 60*v_{1f}+ 12

v_{1f} = -0.2 m/s

So boy will go back with speed 0.2 m/s

Part b)

Since the boy and girl will always exert same force on each other by Newton's III law so it has no it matter whether the boy pushed the girl, the girl pushed the boy, or they put their hands together and pushed each other away.

As in all above cases the as per Newton's III law the force on them is always equal and opposite.

6 0
3 years ago
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