KE = 2000 J
Explanation:
KE = (1/2)mv^2
= (1/2)(0.100 kg)(200 m/s)^2
= 2000 J
relation between potential difference and electric field is given as

so here we know that
d = 3 cm



So now when plates are separated to 4 cm distance carefully
the potential difference between them will change but the electric field between them will remain constant
So at distance of 4 cm also the electric field will be E = 1000 N/C
Answer:
Frequency, f = 1 unit
Explanation:
It is given that,
Period of the wave, T = 1 unit
We need to find the frequency of the wave. There exist an inverse relationship between period and the frequency of the wave. It is given by :

Or


f = 1 unit
So, the frequency of the wave is 1 unit. Hence, this is the required solution.
Answer
The frequency and the period are 45 cycles/second and 0.023 seconds
Explanation:
The frequency of the engine is given by :

We have, the engine increases its performance from zero to 2700 rpms.
Frequency,

The time period of the engine is given by :
T = f/f
So,

Hence, the required frequency and the period are 45 cycles/second and 0.023 seconds respectively.