Answer:
2nd option
Step-by-step explanation:
Express the sum of the 2 polynomials by removing the parenthesis , so
5
- 2x³ + x + 4 - 3
+ 2x³ - 5x ← collect like terms
= 9 - 3 - 4x
Sal: 25 +5x = 240
Divide 5 from both sides so it would be 5+ x=240/5
Subtract 5 from both sides x=48-5
X= 43
Elena: 15 + 5x=300
Divide 5 from both sides so it would be 3 +x=300/5
Subtract 15 from both sides x=60-3
X=57
So Sal jogged for 43 minutes. While Elena jogged for 57 minutes
Answer:
a) 6 gigabytes
b) $100
Step-by-step explanation:
Let c represent the total cost in dollars and d represent the amount of data used in gigabytes.
For the first smartphone
One smartphone plan costs $52 per month for talk and messaging and $8 per gigabyte of data used each month.
Equation =
c = 52 + 8d
For the Second smartphone
A second smartphone plan costs $82 per month for talk and messaging and $3 per gigabyte of data used each month.
Equation =>
c = 82 + 3d
How many gigabytes would have to be used for the plans to cost the same?
We would equate both cost to each other
52 + 8d = 82 + 3d
Collect like terms
8d - 3d = 82 - 52
5d = 30
d = 30/5
d = 6
Therefore,
a) The number of gigabytes for the cost of both Smartphone data plans to be the same = 6 gigabytes.
b) The cost of both plans if 6 gigabytes is used =>
c = 52 + 8d
c = 52 + 8 × 6
c = $100
9514 1404 393
Answer:
Step-by-step explanation:
The place value of a digit to the right of the decimal point is 10 to the negative power of the digit count. The 1st digit right of the decimal point has a place value of 10^-1.
Here, the most significant digit of 0.000000016 is in the 8th place to the right of the decimal point, so its place value is 10^-8.
0.000000016 = 1.6×10^-8
Another way to write the same number is 1.6E-8. (The "E" is a stand-in for ×10^.)
_____
Your (graphing or scientific) calculator or a spreadsheet can display this in scientific notation for you.
__
That many nanoseconds, as this problem states, would be 1.6×10^-17 seconds. "Nano" is an SI prefix meaning 10^-9.
Check the picture below.
so, bearing in mind that, the radius and height are two sides in a right-triangle, thus both are at a ratio of each other, thus the radius is at 3:4 ratio in relation to the height.
![\bf 12\pi =\cfrac{\pi \cdot 3^2h^2 h}{4^2}\implies 12\pi =\cfrac{9\pi h^3}{16}\implies \cfrac{192\pi }{9\pi }=h^3 \\\\\\ \sqrt[3]{\cfrac{192\pi }{9\pi }}=h\implies \sqrt[3]{\cfrac{64}{3}}=h\implies \cfrac{4}{\sqrt[3]{3}}=h \\\\\\ \cfrac{4}{\sqrt[3]{3}}\cdot \cfrac{\sqrt[3]{3^2}}{\sqrt[3]{3^2}}=h\implies \cfrac{4\sqrt[3]{9}}{\sqrt[3]{3^3}}=h\implies \cfrac{4\sqrt[3]{9}}{3}=h](https://tex.z-dn.net/?f=%5Cbf%2012%5Cpi%20%3D%5Ccfrac%7B%5Cpi%20%5Ccdot%203%5E2h%5E2%20h%7D%7B4%5E2%7D%5Cimplies%2012%5Cpi%20%3D%5Ccfrac%7B9%5Cpi%20h%5E3%7D%7B16%7D%5Cimplies%20%5Ccfrac%7B192%5Cpi%20%7D%7B9%5Cpi%20%7D%3Dh%5E3%0A%5C%5C%5C%5C%5C%5C%0A%5Csqrt%5B3%5D%7B%5Ccfrac%7B192%5Cpi%20%7D%7B9%5Cpi%20%7D%7D%3Dh%5Cimplies%20%5Csqrt%5B3%5D%7B%5Ccfrac%7B64%7D%7B3%7D%7D%3Dh%5Cimplies%20%5Ccfrac%7B4%7D%7B%5Csqrt%5B3%5D%7B3%7D%7D%3Dh%0A%5C%5C%5C%5C%5C%5C%0A%5Ccfrac%7B4%7D%7B%5Csqrt%5B3%5D%7B3%7D%7D%5Ccdot%20%5Ccfrac%7B%5Csqrt%5B3%5D%7B3%5E2%7D%7D%7B%5Csqrt%5B3%5D%7B3%5E2%7D%7D%3Dh%5Cimplies%20%5Ccfrac%7B4%5Csqrt%5B3%5D%7B9%7D%7D%7B%5Csqrt%5B3%5D%7B3%5E3%7D%7D%3Dh%5Cimplies%20%5Ccfrac%7B4%5Csqrt%5B3%5D%7B9%7D%7D%7B3%7D%3Dh)
