Explanation:
According to the law of conservation of energy
,
Potential energy = kinetic energy
I = 
![mgh = [\frac{1}{2} \times mv^{2}] + [\frac{1}{2} \times (\frac{mr^{2}}{2}) \frac{v^{2}}{r^{2}}]](https://tex.z-dn.net/?f=mgh%20%3D%20%5B%5Cfrac%7B1%7D%7B2%7D%20%5Ctimes%20mv%5E%7B2%7D%5D%20%2B%20%5B%5Cfrac%7B1%7D%7B2%7D%20%5Ctimes%20%28%5Cfrac%7Bmr%5E%7B2%7D%7D%7B2%7D%29%20%5Cfrac%7Bv%5E%7B2%7D%7D%7Br%5E%7B2%7D%7D%5D)
mgh = ![[\frac{1}{2} \times mv^{2}] + [\frac{1}{4} \times mv^{2}]](https://tex.z-dn.net/?f=%5B%5Cfrac%7B1%7D%7B2%7D%20%5Ctimes%20mv%5E%7B2%7D%5D%20%2B%20%5B%5Cfrac%7B1%7D%7B4%7D%20%5Ctimes%20mv%5E%7B2%7D%5D)
v = 7.4 m/s
thus, we can conclude that the translational speed of the cylinder when it leaves the incline is 7.4 m/s.
Answer:
The magnetic flux through the desk surface is 
.
Explanation:
Given that,
Magnetic field B = 0.42 T
Angle =68°
We need to calculate the magnetic flux
Where, B = magnetic field
A = area
Put the value into the formula
Hence, The magnetic flux through the desk surface is .
Answer:
The tendency of an object to resist changes in its state of motion varies with mass. Mass is that quantity that is solely dependent upon the inertia of an object. The more inertia that an object has, the more mass that it has. A more massive object has a greater tendency to resist changes in its state of motion.
Explanation:
Answer:
Resultant force = 8.6N
Explanation:
Using Pythogorus' theorem
Resultant force = 8.6N
Answer:
F = 8.6 10⁻¹² N
Explanation:
For this exercise we use the law of conservation of energy
Initial. Field energy with the electron at rest
Em₀ = U = q ΔV
Final. Electron with velocity, just out of the electric field
Emf = K = ½ m v²
Em₀ = Emf
e ΔV = ½ m v²
v =√ 2 e ΔV / m
v = √(2 1.6 10⁻¹⁹ 51400 / 9.1 10⁻³¹)
v = √(1.8075 10¹⁶)
v = 1,344 10⁸ m / s
Now we can use the equation of the magnetic force
F = q v x B
Since the speed and the magnetic field are perpendicular the force that
F = e v B
F = 1.6 10⁻¹⁹ 1.344 10⁸ 0.4
For this exercise we use the law of conservation of energy
Initial. Field energy with the electron at rest
Emo = U = q DV
Final. Electron with velocity, just out of the electric field
Emf = K = ½ m v2
Emo = Emf
.e DV = ½ m v2
.v = RA 2 e DV / m
.v = RA (2 1.6 10-19 51400 / 9.1 10-31)
.v = RA (1.8075 10 16)
.v = 1,344 108 m / s
Now we can use the equation of the magnetic force
F = q v x B
Since the speed and the magnetic field are perpendicular the force that
F = e v B
F = 1.6 10-19 1,344 108 0.4
F = 8.6 10-12 N
