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3 years ago

A top fuel dragster covers the quarter mile in 4.5 seconds. What is it's speed in miles per hour

Physics

2 answers:

Tju [1.3M]3 years ago

7 0

Answer: The speed of top fuel dragster is 200 miles/hr

Explanation:

We are given:

Speed of top fuel dragster = quarter mile in 4.5 seconds = 0.25 mil/4.5 sec

To calculate the speed of top fuel dragster in miles per hour, we use the conversion factor:

1 hr = 3600 seconds

Converting the speed in miles per hour, we get:

$\Rightarrow (\frac{0.25mil}{4.5s}\times (\frac{3600s}{1hr})\\\\\Rightarrow 200mil/hr$

Hence, the speed of top fuel dragster is 200 miles/hr

gladu [14]3 years ago

6 0

Distance in Miles (.25) x 3600 (seconds in an hour) / time in seconds = 200 MPH. Drag racing calculates the top speed via a speed trap starting 66 feet from the finish line.

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You are out running and the first mile takes you 10 minutes. The second mile takes you 20 minutes. This is an example of

cupoosta [38]

If Equal distance is traveled in equal interval of time then it is known as uniform motion in which velocity of object will remain same.

Then if distance covered will be same and the time taken to cover same distance is decreasing then it shows that speed is increasing with time due to which it took less time to cover same distance. This is also known as positive acceleration.

Now if the distance covered will be same and time taken to cover same distance is increasing then it shows that speed is decreasing with time due to which it took more time to cover the same distance. This is also known as negative acceleration.

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3 years ago

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Explanation:

(a) We have,

Length of solenoid, l = 55 cm = 0.55 m

Diameter of the solenoid, d = 10 cm

Radius, r = 5 cm = 0.05 m

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$L=\dfrac{\mu_o N^2A}{l}$

A is area

$L=\dfrac{4\pi \times 10^{-7}\times (1000)^2\times \pi (0.05)^2}{0.55}\\\\L=0.0179\ H\\\\L=17.9\ mH$

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A train, traveling at a constant speed of 25.8 m/s, comes to an incline with a constant slope. While going up the incline, the t

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The final velocity of the train after 8.3 s on the incline will be 12.022 m/s.

Answer:

Explanation:

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So we know the values for parameters u,a and t. Since, the train slows down on the slope, so the acceleration value will have negative sign with the magnitude of acceleration. Then

v = 25.8 + (-1.66×8.3)

v =12.022 m/s.

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