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2 years ago

Twenty minus the quotient of 7 and x is the same as twice x.

Mathematics

1 answer:

givi [52]2 years ago

6 0

20-7/x=2x
Here you go
:)

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All help is much appreciated please and thank you

scoundrel [369]

Anddd Similar traingles for one more time.

Here,
RQ/RP = RS/RT = QS/PT = 1/2

Using the values of QS and PT will give,

$\frac{y}{y + 46} = \frac{1}{2} \\ \\ 2y =y + 46 \\ \\ y = 46$

Therefore y= 46 units.

6 0

3 years ago

ASAP PLEASE HELP!! “Find the quotient”

elena-14-01-66 [18.8K]

Answer:

The quotient is $\frac{x(2x-3)}{7}$ answer (D)

Step-by-step explanation:

$\frac{2x-3}{x}$ ÷ $\frac{7}{x^{2} }$

In division with fractions we reverse the fraction after division sign and change division sign to multiplication sine

$\frac{2x-3}{x}$ × $\frac{x^{2} }{7}$

$\frac{2x-3}{1}$ × $\frac{x}{7}$

$\frac{x(2x-3)}{7}$

4 0

4 years ago

Which of the follow expressions are equivalent to (3^4)^-2 • (3^5)^3

Fiesta28 [93]

Answer:

3^7

Step-by-step explanation:

3 0

3 years ago

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6 1/2 yards of ribbon cost $8.22 WHAT IS THE UNIT RATE

timama [110]

$1.26 per yard. See photo for explanation.

6 0

3 years ago

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Im Triggered Pls Dont DELETE!

stepladder [879]

I'm assuming you mean $f(x) = (e^x + 5x)^2$ , not $f(x) = (e x + 5x)2$ , like your prompt suggests.

First, let's figure out what rule we can use. A likely noticeable one is the Power Rule, which says the following:

$\dfrac{d}{dx} [u^a] = a(u)^{a-1} du$

Applying this, we can solve for the derivative:

$f'(x) = 2(e^x + 5x) (e^x + 5)$

Apply the Power Rule

While you can simplify the expression to your liking, I believe that this form is not overly complex and will thus leave it as is.

Thus, our answer is:

$f'(x) = \boxed{2 (e^x + 5x)(e^x + 5)}$

7 0

3 years ago

Read 2 more answers