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lord [1]
3 years ago
15

Give the oxidation numbers of all atoms in NaMnO4

Chemistry
1 answer:
trasher [3.6K]3 years ago
3 0
Oxygen is -2, Na is +1, and Mn is +7
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Anyone? Please help
snow_tiger [21]

Answer:

The limiting reacting is O2

Explanation:

Step 1: data given

Number of moles O2 = 21 moles

Number of moles C6H6O = 4.0 moles

Step 2: The balanced equation

C6H6O + 7O2 → 6CO2 + 3H2O

Step 3: Calculate the limiting reactant

For 1 mol C6H6O we need 7 moles O2 to produce 6 moles CO2 and 3 moles H2O

O2 is the limiting reactant. It will completely be consumed (21 moles).

C6H6O is in excess.

For 7 moles O2 we need 1 mol C6H6O

For 21 moles O2 we'll need 21/7 = 3 moles C6H6O

There will remain 4.0 - 3.0 = 1 mol C6H6O

Step 4: calculate products

For 1 mol C6H6O we need 7 moles O2 to produce 6 moles CO2 and 3 moles H2O

For 21 moles O2 we'll have 6/7 * 21 = 18 moles CO2

For 21 moles O2 we'll have 3/7 * 21 = 9 moles H2O

The limiting reacting is O2

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4 years ago
The interaction of two or more drugs at the same receptor site in which one blocks the action of the other is
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The answer is I

The correct way of writing this would be silver(I) sulfide, but silver sulfide without the (I) is also OK because it isn't always writte, nor is it necessary to write the (I). 
 
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Which of the following is not part of Dalton's atomic theory?
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