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2 years ago

Calculate how many moles of water molecules were produced in the combustion of ethanol in oxygen.

Chemistry

1 answer:

nadya68 [22]2 years ago

8 0

There are 3 moles of water formed in the complete combustion of ethane.

<h3>What is Combustion Reaction? </h3>

Combustion is a chemical reaction between substances , usually including oxygen and usually accompanied by the generation of heat and light in form of flame.

For example , the wood burning in a fireplace. The wood is a fuel which continuously react with oxygen in the air in a combustion reaction.

When ethane goes for combustion

reaction ,

C2H6+7/2 O2→2CO2+ 3H2O

As you can see on the above reaction 3 moles of water molecules are produced .

to learn More about Combustion Reaction click here brainly.com/question/15117038

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What is the oxidation number of Cl in chlorate ion ClO3?

Kryger [21]

The correct answer to this question is "5." the oxidation number of cl in ClO3 will be a positive 5 because oxygen is naturally a -2 charge. times that by three and then account for the negative charge of the CLO3- ion.

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3 years ago

Read 2 more answers

What is the formula for tin(IV) sulfide?<br> A. Sn4S<br> B. SnS2<br> C. Sns<br> D. SnS4

defon

Answer:

$SnS_{2}$

Explanation:

The formula for tin(IV) sulfide is SnS $_{2}$

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3 years ago

Is Lilium lancifolium Heterotroph, Autotroph, or Both

Sphinxa [80]

Lilium lancifolium is an autotroph since it is a plant and makes its own food through photosynthesis.

4 0

3 years ago

An unknown gaseous substance has a density of 1.06 g/L at 31 °C and 371 torr. If the substance has the following percent composi

Anarel [89]

Answer:

C) C4H6 - Right answer

Explanation:

Let's combine the Ideal Gases Law with density to get the molecular formula for the unknown gas.

Density = mass / volume

1.06 g /L means that 1.06 grams of compound occupy 1 liter of volume.

P . V = n . R . T

Pressure in Torr must be converted to atm

760 Torr are 1 atm

371 Torr are __ (371 .1)/760 = 0.488 atm

0.488 atm . 1L = 1.06g/MM . 0.082 . 304K

(0.488 atm . 1L) / 0.082 . 304K = 1.06g/ MM

Mass / Molar mass = Moles → That's why the 1.06 g / MM

0.0195 mol = 1.06g / MM

1.06g/0.0195 mol = MM → 54.3 g/m

Now, let's use the composition

100 g of compound have 88.8 g of C

54.3 g of compound have ___ (54.3 . 88.8) /100 = 48 g of C

100 g of compound have 11.2 g of H

54.3 g of compound have __ (54.3 . 11.2)/100 = 6 g of H

48 g of C are included un 4 atoms

6 g of H are included in 6 atoms

4 0

3 years ago

Write the Iconic Bond to Metals

Nutka1998 [239]

<u>Answer:</u> The ionic compound formed is magnesium chloride having formula $MgCl_2$

<u>Explanation:</u>

Ionic compound is defined as the compound which is formed by complete transfer of electrons from one atom to another atom.

The atom which looses the electron is known as electropositive atom and the atom which gains the electron is known as electronegative atom. This bond is usually formed between a metal and a non-metal.

Magnesium is the 12th element of the periodic table having electronic configuration of $1s^22s^22p^63s^2$

This element will loose 2 electrons to form $Mg^{2+}$ ion

Chlorine is the 17th element of the periodic table having electronic configuration of $1s^22s^22p^63s^23p^5$

This element will gain 1 electron to form $Cl^{-}$ ion

So, for every 1 atom of magnesium, 2 atoms of chlorine are required. Thus, the chemical formula becomes $MgCl_2$

Hence, the ionic compound formed is magnesium chloride having formula $MgCl_2$

6 0

3 years ago