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1 year ago

The chemical equation of photosynthesis includes 6o2. which best describes this substance?

1 answer:

4 0

The chemical equation of photosynthesis includes 6 $O_{2}$ . -----a gas produced during photosynthesis best describes this substance

Elaborate:

During photosynthesis plants use carbon dioxide, water and sunlight to make sugar (glucose) and a waste product, oxygen gas.

the equation of this process can be:

6 $CO_{2}$ + 6 $H_{2} O$ + light energy → $C_{6} H_{12} O_{6}$ + 6 $O_{2}$

carbon dioxide + water + light → glucose + oxygen

Is 6 $O_{2}$ a product of photosynthesis?

In photosynthesis, energy from light is used to convert carbon dioxide and water into glucose and oxygen. For 6 carbon dioxide and 6 water molecules, 1 glucose molecule and 6 oxygen molecules are produced.

What happens to sugar water oxygen and carbon dioxide during photosynthesis?

During photosynthesis, plants take in carbon dioxide and water from the air and soil. Within the plant cell, the water is oxidized, meaning it loses electrons, while the carbon dioxide is reduced, meaning it gains electrons. This transforms the water into oxygen and the carbon dioxide into glucose.

Learn more about photosynthesis:

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Calculate the hight of a column of liquid glycerol in meters required to exert the same pressure as 3.02 m if CCl4?

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Approximately $3.81\; \rm m$ .

Explanation:

Look up the density $\rho$ of carbon tetrachloride, $\rm CCl_4$ , and glycerol:

Density of carbon tetrachloride: approximately $1.59\times 10^{3}\; \rm kg \cdot m^{-3}$ .
Density of glycerol: approximately $1.26\times 10^{3}\; \rm kg \cdot m^{-3}$ .

Let $g$ denote the gravitational field strength. (Typically $g \approx 9.81\; \rm N \cdot kg^{-1}$ near the surface of the earth.) For a column of liquid with a height of $h$ , if the density of the liquid is $\rho$ , the pressure at the bottom of the column would be:

$P = \rho\cdot g \cdot h$ .

The pressure at the bottom of this carbon tetrachloride column would be:

$\begin{aligned} P &= \rho \cdot g \cdot h \\ & \approx 1.59\times 10^{3} \; \rm kg \cdot m^{-3} \times 9.81\; \rm N \cdot kg^{-1} \times 3.02 \; \rm m \approx 4.71 \times 10^{4} \; \rm N \cdot m^{-2} \end{aligned}$ .

Rearrange the equation $P = \rho\cdot g \cdot h$ for $h$ :

$\displaystyle h = \frac{P}{\rho \cdot g}$ .

Apply this equation to calculate the height of the liquid glycerol column:

$\begin{aligned}h &= \frac{P}{\rho \cdot g} \\ &\approx \frac{4.71 \times 10^{4}\; \rm N \cdot m^{-2}}{1.26 \times 10^{3}\; \rm kg \cdot m^{-3} \times 9.81\; \rm N \cdot kg^{-1}} \approx 3.81\; \rm m\end{aligned}$ .

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