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10 months ago

The chemical equation of photosynthesis includes 6o2. which best describes this substance?

1 answer:

4 0

The chemical equation of photosynthesis includes 6 $O_{2}$ . -----a gas produced during photosynthesis best describes this substance

Elaborate:

During photosynthesis plants use carbon dioxide, water and sunlight to make sugar (glucose) and a waste product, oxygen gas.

the equation of this process can be:

6 $CO_{2}$ + 6 $H_{2} O$ + light energy → $C_{6} H_{12} O_{6}$ + 6 $O_{2}$

carbon dioxide + water + light → glucose + oxygen

Is 6 $O_{2}$ a product of photosynthesis?

In photosynthesis, energy from light is used to convert carbon dioxide and water into glucose and oxygen. For 6 carbon dioxide and 6 water molecules, 1 glucose molecule and 6 oxygen molecules are produced.

What happens to sugar water oxygen and carbon dioxide during photosynthesis?

During photosynthesis, plants take in carbon dioxide and water from the air and soil. Within the plant cell, the water is oxidized, meaning it loses electrons, while the carbon dioxide is reduced, meaning it gains electrons. This transforms the water into oxygen and the carbon dioxide into glucose.

Learn more about photosynthesis:

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Suppose you needed to measure exactly 15.0 mL of water for an

s344n2d4d5 [400]

Answer:

A 50-mL volumetric cylinder with 0.1-mL accuracy scale should be used for this purpose since three significant figures of accuracy are required.

Explanation:

Hello,

A 50-mL volumetric cylinder with 0.1-mL accuracy scale should be used for this purpose since three significant figures of accuracy are required.

Best regards.

6 0

3 years ago

Read 2 more answers

John dissolves .5g of a white powder in 25g of benzene (FP 5oC) (kf benzene is 5.1) and finds the solution freezes at 3.7oC. Det

navik [9.2K]

Answer:

The compound has a molar mass of 78.4 g/mol

Explanation:

Step 1: data given

Mass of a sample = 0.5 grams

Mass of benzene = 25 grams

Freezing poing = 5 °C

Kf of benzene = 5.1 °C/m

Freezing point solution = 3.7 °C

Step 2: Calculate molality

ΔT = i*Kf*m

⇒with ΔT = the freezing point depression = 5.0 - 3.7 = 1.3 °C

⇒with i = the can't hoff factor = 1

⇒with Kf = the freezing point depression constant of benzene = 5.1 °C/m

⇒with m = the molality

1.3 = 5.1 * m

m = 1.3 / 5.1

m = 0.255 moles /kg

Step 3: Calculate moles

Molality = moles / mass benzene

0.255 molal = moles / 0.025 kg

Moles = 0.255 molal * 0.025 kg

Moles = 0.006375 moles

Step 4: Calculate molar mass of the compound

Molar mass compund = mass / moles

Molar mass compound = 0.5 grams / 0.006375 moles

Molar mass compound = 78.4 g/mol

The compound has a molar mass of 78.4 g/mol

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2 years ago

If we were to dissolve iodine in alcohol, which term would describe the alcohol?

marishachu [46]

It will be Solvent the term that would describe the alcohol will be solvent.

4 0

3 years ago

If 3.49 g of silver chloride, AgCl, is produced from the reaction of 5.95 g AgNO3 with excess BaCl2,

TEA [102]

Answer:

that not of i grade sorry

Explanation:

3 0

3 years ago

A solution is initially 0.10m in mg2+(aq) and 0.10m in fe2+(aq). solid naoh is slowly added. what is the concentration of fe2+ w

dexar [7]

Mg(OH)₂ ⇄ Mg²⁺ + 2 OH⁻

Ksp = [Mg²⁺] [OH⁻]²

6.0 x 10⁻¹⁰ = 0.10 x [OH⁻]²

[OH⁻] = 7.746 x 10⁻⁵ M

when Mg(OH)₂ 1st precipitates, [OH⁻] = 7.746 * 10⁻⁵ M

Fe(OH)₂ <—> Fe²⁺ + 2OH⁻

Ksp = [Fe²⁺] [OH⁻]²

7.9 x 10⁻¹⁶ = [Fe²⁺] x (7.746 x 10⁻⁵)²

[Fe²⁺] = 1.32 x 10⁻⁷ M

Answer: 1.32 x 10⁻⁷ M

5 0

2 years ago