You would think that the bag of nails would have more mass but their masses are identical. <span>If you were to put them both in a vacuum chamber and let them fall from a great height, they would fall the same speed. The vacuum chamber would suck all of the air out of the cotton balls, thus making it heavier and weigh the same as the bag of nails.
Hopefully this is helpful and makes sense.</span>
Answer:
The 2 in the formula means that, there are 2 phosphate anions that forms the salt.
Explanation:
Magnesium phosphate is a ionic salt.
The formula indicates that 3 moles of Mg and 2 moles of anion phosphate are contained in 1 mol of compound.
3Mg²⁺ + 2PO₄⁻³ → Mg₃(PO₄)₂
The phosphate anion comes from phosphoric acid and it is generated when the acid loses the 3 protons.
H₃PO₄ → 3H⁺ + PO₄⁻³
Phosphate has a negative charge of -3, so when it bond to magnesium, which has a charge of +2, there must be 3 magnesium and 2 phosphate to make a global charge +6 -6 in the ions
Answer: option E. Evaporation to dryness
Explanation:
> How many valence electrons does a helium atom have?
The electron configuration of Helium is simply 1s2. We see
that its outermost shell is the s shell and it contains 2 electrons, therefore
the number of valence electrons is also 2.
> What is the formula of the ion formed when potassium
achieves noble-gas electron configuration?
Potassium has a electron configuration of [Ar] 4s1. To
have an electron configuration of only [Ar] which is a noble gas, the one electron
from 4s1 should be removed, hence:
<span>K+</span>
Answer:
73.4% is the percent yield
Explanation:
2KClO₃ → 2KCl + 3O₂
This is a decomposition reaction, where 2 moles of potassium chlorate decompose to 2 moles of potassium chloride and 3 moles of oxygen.
We determine the moles of salt: 400 g . 1. mol /122.5g= 3.26 moles of KClO₃
In the theoretical yield of the reaction we say:
2 moles of potassium chlorate can produce 3 moles of oxygen
Therefore, 3.26 moles of salt, may produce (3.26 . 3) /2 = 4.89 moles of O₂
The mass of produced oxygen is: 4.89 mol . 32 g /1mol = 156.6g
But, we have produced 115 g. Let's determine the percent yield of reaction
Percent yield = (Produced yield/Theoretical yield) . 100
(115g / 156.6g) . 100 = 73.4 %
