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andriy [413]
1 year ago
14

A car moves with constant velocity along a straight road. Its position is x1 = 0 m at t1 = 0 s and is x2 = 32 m at t2 = 2.0 s .

Answer the following by considering ratios, without computing the car's velocity. 1. What is the car's position at t = 1.0 s ? 2. What will be its position at t = ? answers pleaseeeee
Physics
1 answer:
Lerok [7]1 year ago
3 0

Without computing the car's velocity, the car's position at t = 1.0 s will be x = 16m

<h3>Position - Time Graph</h3>

The gradient of the position time graph is speed.

Given that a car moves with constant velocity along a straight road. Its position is x1 = 0 m at t1 = 0 s and is x2 = 32 m at t2 = 2.0 s.

The gradient m = Δx ÷ Δt

m = (32 - 0) / (2 - 0)

m = 32 / 2

m = 16 m/s

Without computing the car's velocity, the car's position at t = 1.0 s will be

32 / 2 = x / 1

x = 16 m

Therefore, without computing the car's velocity, the car's position at t = 1.0 s will be x = 16m

Learn more about Position Time Graph here: brainly.com/question/18388330

#SPJ1

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Lemur [1.5K]

Answer:

The factor of the diameter is 0.95.

Explanation:

Given that,

Power of old light bulb = 54.3 W

Power = 60 W

We know that,

The resistance is inversely proportional to the diameter.

R\propto\dfrac{1}{D}

The power is inversely proportional to the resistance.

P\propto\dfrac{1}{R}

P\propto D^2

We need to calculate the factor of the diameter of the filament reduced

Using relation of power and diameter

\dfrac{P_{i}}{P_{f}}=\dfrac{D_{i}^2}{D_{f}^2}

Put the value into the formula

\dfrac{D_{i}^2}{D_{f}^2}=\dfrac{54.3}{60}

\dfrac{D_{i}}{D_{f}}=0.95

D_{i}=0.95 D_{f}

Hence, The factor of the diameter is 0.95.

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3 years ago
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The _____ of a mechanical wave is a direct measure of its energy.
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I think it's amplitude

6 0
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What is the frequency of orange light is it has a wavelength of 6.2 x 10^-6<br> meters?
Tanya [424]

λ=v/f

λ-wavelength

v-speed

f-frequency

we have the wavelength(6.2 x 10^-6meters) and we use the speed of light which is equal to 3*10^8m/s

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f=(3*10^8m/s)/(6.2*10^-6)≈0.48*10^14Hz

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A plane is landing. It started at 400m/s and ended up at 50m/s after 30 seconds. What is it's acceleration?
quester [9]

Give u = start velocity

        v = end velocity

v = u + at

50 = 400 + a*30

30a = -350

a = -116.67 m/s^{2}

**Why the accecleration is negative number**

Because displacement, velocity, and acceleration are VECTOR QUANTITIES.

Vector Quantity must have direction.

4 0
3 years ago
In the diagram, q1 = +6.60*10^-9 C and q2 = +3.10*10^-9 C. Find the magnitude of the total electric field at point P. pls help?
kirza4 [7]

Answer:

|E(t)| = 1258,46 [N/C]

α = 67,5⁰  (angle with respect x-axis)

Explanation:

E(t)  Electric Field is a vector, so we need to determine module and direction

E(t)  =  E(q₁)  + E (q₂)  Where E(q₁) and E (q₂) are electric fields due to electric charge q₁ and q₂  respectively.

E(q₁) = K * q₁/ (d₁)²         K = 9 *10⁹   [N*m²/C²]    d₁ = 0,350 m

E(q₁) = 9 *10⁹ * 6,6*10⁻⁹ / 0,1225      [N*m²/C²] *C/m²

E(q₁) = 484,9 [N/C]

E(q₂) =  9 *10⁹ * 3,1*10⁻⁹ / 0,024025

E(q₂) = 1161,29

Then

|E(t)| = √ |Eq₁|² + |Eq₂|²

|E(t)| = √ ( 484,9)² +( 1161,29)²

|E(t)| = √ 235128 + 1348594,46

|E(t)| = 1258,46 [N/C]

And tanα = 1161,29/484,9        tanα =  2,395      α = 67,5⁰

The angle of the vector electric field with the x-axis

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3 years ago
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