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andriy [413]
1 year ago
14

A car moves with constant velocity along a straight road. Its position is x1 = 0 m at t1 = 0 s and is x2 = 32 m at t2 = 2.0 s .

Answer the following by considering ratios, without computing the car's velocity. 1. What is the car's position at t = 1.0 s ? 2. What will be its position at t = ? answers pleaseeeee
Physics
1 answer:
Lerok [7]1 year ago
3 0

Without computing the car's velocity, the car's position at t = 1.0 s will be x = 16m

<h3>Position - Time Graph</h3>

The gradient of the position time graph is speed.

Given that a car moves with constant velocity along a straight road. Its position is x1 = 0 m at t1 = 0 s and is x2 = 32 m at t2 = 2.0 s.

The gradient m = Δx ÷ Δt

m = (32 - 0) / (2 - 0)

m = 32 / 2

m = 16 m/s

Without computing the car's velocity, the car's position at t = 1.0 s will be

32 / 2 = x / 1

x = 16 m

Therefore, without computing the car's velocity, the car's position at t = 1.0 s will be x = 16m

Learn more about Position Time Graph here: brainly.com/question/18388330

#SPJ1

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You have a 3.00-liter container filled with N₂ at 25°C and 4.45 atm pressure connected to a 2.00-liter container filled with Ar
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P\propto \frac{1}{V}

Thus, the expression for final pressure in the two containers will be:

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P=\frac{P_1V_1+P_2V_2}{V}

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V_2 = volume of Ar gas = 2.00 L

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