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andriy [413]
1 year ago
14

A car moves with constant velocity along a straight road. Its position is x1 = 0 m at t1 = 0 s and is x2 = 32 m at t2 = 2.0 s .

Answer the following by considering ratios, without computing the car's velocity. 1. What is the car's position at t = 1.0 s ? 2. What will be its position at t = ? answers pleaseeeee
Physics
1 answer:
Lerok [7]1 year ago
3 0

Without computing the car's velocity, the car's position at t = 1.0 s will be x = 16m

<h3>Position - Time Graph</h3>

The gradient of the position time graph is speed.

Given that a car moves with constant velocity along a straight road. Its position is x1 = 0 m at t1 = 0 s and is x2 = 32 m at t2 = 2.0 s.

The gradient m = Δx ÷ Δt

m = (32 - 0) / (2 - 0)

m = 32 / 2

m = 16 m/s

Without computing the car's velocity, the car's position at t = 1.0 s will be

32 / 2 = x / 1

x = 16 m

Therefore, without computing the car's velocity, the car's position at t = 1.0 s will be x = 16m

Learn more about Position Time Graph here: brainly.com/question/18388330

#SPJ1

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A particle moving on a circle has a velocity of 5 m/s and a normal acceleration of 10 m/s^2. What is the radius of the circle?
dybincka [34]

Answer:

Radius of the circle will be 2.5 m

Explanation:

We have given velocity of particle moving in the circle v = 5 m/sec

Acceleration of particle in the circle a=10m/sec^2

We have to find the radius of the circle

We know that acceleration is given by a=\frac{v^2}{r}

So 10=\frac{5^2}{r}

r=\frac{25}{10}=2.5m

So radius of the circle will be 2.5 m

3 0
3 years ago
Mamie clark was a psychologist who is known for her research on ?
koban [17]

Mamie Phipps Clark is a noted woman psychologist, best known for her research on race, self-esteem, and child development. Her work alongside her husband, Kenneth Clark, was critical in the 1954 Brown vs Board of Education case and she was the first black woman to earn a degree from Columbia University.

4 0
3 years ago
Read 2 more answers
The eyes of some reptiles are sensitive to 850 nm light. If the minimum energy to trigger the receptor at this wavelength is 3.1
mr_godi [17]

Answer:

Minimum number of photons required is 1.35 x 10⁵

Explanation:

Given:

Wavelength of the light, λ = 850 nm = 850 x 10⁻⁹ m

Energy of one photon is given by the relation :

E=\frac{hc}{\lambda}    ....(1)

Here h is Planck's constant and c is speed of light.

Let N be the minimum number of photons needed for triggering receptor.

Minimum energy required for triggering receptor, E₁ = 3.15 x 10⁻¹⁴ J

According to the problem, energy of N number of photons is equal to the energy required for triggering, that is,

E₁ = N x E

Put equation (1) in the above equation.

E_{1}=N\times\frac{hc}{\lambda}

Substitute 3.15 x 10⁻¹⁴ J for E₁, 850 x 10⁻⁹ m for λ, 6.6 x 10⁻³⁴ J s for h and 3 x 10⁸ m/s for c in the above equation.

3.15\times10^{-14} =N\times\frac{6.6\times10^{-34}\times3\times10^{8}}{850\times10^{-9}}

N = 1.35 x 10⁵

8 0
3 years ago
A sports car accelerates from rest for 5 seconds reaching a velocity of 23.0 m/s.
denis-greek [22]

Answer:

<h2>4.6 m/s²</h2>

Explanation:

The acceleration of an object given it's velocity and time taken can be found by using the formula

<h3>a =  \frac{v - u}{t}  \\</h3>

where

v is the final velocity

u is the initial velocity

t is the time taken

a is the acceleration

Since the body is from rest u = 0

From the question we have

a =  \frac{23 - 0}{5}  =  \frac{23}{5}  \\

We have the final answer as

<h3>4.6 m/s²</h3>

Hope this helps you

4 0
2 years ago
If you put 120 volts of electricity through a pickle, the pickle will smoke and start glowing orange-yellow. The light is emitte
Alona [7]

Answer:

2.11eV

Explanation:

We know that speed of light is it's wavelength times frequency.

\therefore f=v/\lambda\\=(3\times10^8m/s)/(589mm\times1m/1\times 10^9nm)\\=5.09\times10^1^4s^-1 \ or \ 5.09\times10^1^4Hz

Planck's constant is 6.626\times 10^3^4Js

The energy gap is calculated by multyplying the light's frequency by planck's constant:

E_c=5.09\times10^1^4s^-^1\times 6.626\times10^-^3^4Js\\\\=3.37\times 10^-^1^9J  \ \ \ \ \ \ #1eV=1.06\times 10^-^1^9J\\\\=2.11eV

Hence, the energy gap is 2.11eV

4 0
3 years ago
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