A) 330 N
Explanation: Her weight must be evenly distributed between the chains (assuming they are at an even level), so you divide 660 by 2 and get 330
Answer:
C. My soup will cool down because of radiation.
Explanation:
Since, there is vacuum between hot soup and its outside wall, then heat can not flow through conduction and convection.
The heat then only flows through radiation.
Therefore, the soup will not cool down because of convection or conduction by because of radiation.
satellite originally moves in a circular orbit of radius R around the Earth. Suppose it is moved into a circular orbit of radius 4R.
(i) What does the force exerted on the satellite then become?
eight times larger<span>four times larger </span>one-half as largeone-eighth as largeone-sixteenth as large(ii) What happens to the satellite's speed?<span>eight times larger<span>four times larger </span>one-half as largeone-eighth as largeone-sixteenth as large(iii) What happens to its period?<span>eight times larger<span>four times larger </span>one-half as largeone-eighth as largeone-sixteenth as large</span></span>
<span>
</span>
Answer:

Given:
Mass of the polar bear (m) = 6.8 kg
Speed of the polar bear (v) = 5.0 m/s
To Find:
Kinetic energy of the polar bear (KE)
Explanation:
Formula:

Substituting values of m & v in the equation:





Kinetic energy of the polar bear (KE) = 23002.1 J