Question

Charles’ Law can be expressed mathematically as V=kT. If the constant k for 6.0 L of gas is 0.020 L/K (liters per kelvin), what is the temperature of the gas?

Answer 1

Answer: 300 K

Explanation:

Charles' Law: This law states that volume is directly proportional to the temperature of the gas at constant pressure and number of moles.

$V\propto T$    (At constant pressure and number of moles)

$V=kT$

Given : V= 6.0 L

k= 0.020 L/K

T=?

$6.0=0.020LK^{-1}\times T$

$T=300 K$

Thus temperature of the gas is 300 K.