Answer:
grams of oxygen = 21.40 g
Explanation:
octane → C8H18
The chemical reaction needs to be represented with a chemical equation before solving. The equation also need to be balanced.
C8H18 + O2 → CO2 + H2O
Balanced equation
2C8H18 + 25O2 → 16CO2 + 18H2O
Molar mass of octane = 12 × 8 + 18 = 96 + 18 = 114 g
Mass of octane in the chemical equation = 2 (114) = 228 g
molar mass of oxygen = 32 g
mass of oxygen in the chemical equation = 25 × 32 = 800 g
if 228 g of octane react with 800 g of oxygen
6.1 g of octane will require ? grams of oxygen
cross multiply
grams of oxygen = 6.1 × 800/228
grams of oxygen = 4880
/228
grams of oxygen = 21.4035087719
grams of oxygen = 21.40 g
Answer:

Explanation:
We can use the Ideal Gas Law to calculate the density of the gas.
pV = nRT
n = m/M Substitute for n
pV = (m/M)RT Multiply both sides by M
pVM = mRT Divide both sides by V
pM = (m/V) RT
ρ = m/V Substitute for m/V
pM = ρRT Divide each side by RT

Data:
p = 1.00 bar
M = 49 g/mol
R = 0.083 14 bar·L·K⁻¹mol⁻¹
T = 0 °C = 273.15 K
Calculation:
ρ = (1.00 × 49)/(0.083 14 × 273.15) = 2.2 g/L
The density of the gas is
.
Answer:
35.1 kJ/mol is the expected value for the heat of sublimation of acetic acid.
Explanation:
..[1]
Heat of vaporization of acetic acid = 
..[2]
Heat of fusion of acetic acid = 
Heat of sublimation of acetic acid = 
..[3]
[1] + [2] = [3] (Hess's law)


35.1 kJ/mol is the expected value for the heat of sublimation of acetic acid.
Answer:
- F
- E
- G
- A
- C
- B
- D
Explanation:
Those are the answers in order, BUT the Goldstein and Rutherford ones are confusing me because Rutherford discovered<em> protons</em> and the <em>nuclear atom</em>. Through my research I also noticed that Goldstein contributed to the discovery of the protons made Rutherford, so I listed him as the one who discovered the proton.
I hope this helps! Have a wonderful night! :D
<span>CH3OH and NH3
I HOPE THIS HELPS :D</span>