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ladessa [460]
2 years ago
15

Oceń prawdziwość podanych informacji w układzie okresowym pierwiastki chemiczne są złożone według NIK to jących się liczbą atomo

wych Z Jądro atomowe jest bardzo mały i leży

Chemistry
1 answer:
cluponka [151]2 years ago
3 0
Wow. What language is this?
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What is the number of atoms per unit cell for each metal?
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In the question, the number of atoms per unit cell is required for:
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In polonium, the structure is simple cubic, meaning there are 8 corner atoms, which add up to one atom per unit cell.

B) Manganese (Mn)
The structure of the Mn can be considered to be a body centered cubic (BCC) and the number of atoms for this is 8 corner atoms and 1 central atoms, making a total of 2 atoms per unit cell.

C) Silver (Ag)
Silver has a face centered cubic (FCC) unit cell structure, where there are 8 corner atoms and 6 atoms on the faces, so there are a total of 4 atoms per unit cell.
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Do you think flowers are important to mindkind? If yes explain why in your own words please it would mean a lot!!
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Answer:

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2 years ago
Nitration of 1,4−dimethylbenzene (p−xylene) gives a single product having the molecular formula c8h9no2 in high yield. draw this
GarryVolchara [31]
Structure is in document below.
The mononitration of p-xylene can be easily carried out at 30 degrees C.
Para-xylene<span> (</span><span>p-xylene</span><span>) is an </span>aromatic hydrocarbon, <span>one of the three </span>isomers<span> of </span>dimethylbenzene. Para-xylene is colorless and highly flammable, not acutely toxic and has some <span>narcotic effects.</span>
Download docx
8 0
3 years ago
48g of 02 produce how many grams of Al2O3
bixtya [17]

Taking into account the reaction stoichiometry,  102 grams of Al₂O₃ are formed when 48 grams of O₂ react.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

4 Al + 3 O₂  → 2 Al₂O₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • Al: 4 moles
  • O₂: 3 moles
  • Al₂O₃: 2 moles

The molar mass of the compounds is:

  • Al: 27 g/mole
  • O₂: 32 g/mole
  • Al₂O₃: 102 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

  • Al: 4 moles ×27 g/mole= 108 grams
  • O₂: 3 moles ×32 g/mole= 96 grams
  • Al₂O₃: 2 moles ×102 g/mole= 204 grams

<h3>Mass of Al₂O₃ formed</h3>

The following rule of three can be applied: if by reaction stoichiometry 96 grams of O₂ form 204 grams of Al₂O₃, 48 grams of O₂ form how much mass of Al₂O₃?

mass of Al_{2} O_{3} =\frac{48 grams of O_{2} x204 grams of Al_{2} O_{3}}{96 grams of O_{2}}

<u><em>mass of Al₂O₃= 102 grams</em></u>

Finally, 102 grams of Al₂O₃ are formed when 48 grams of O₂ react.

Learn more about the reaction stoichiometry:

brainly.com/question/24741074

brainly.com/question/24653699

#SPJ1

3 0
1 year ago
Please help, I will love you for life!!
vichka [17]
Here's what I got. Hope it helps.

5 0
3 years ago
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