2 years ago

If the pressure changes from 1 atm to 3 atm, what does the volume of 30 L change to

Chemistry

1 answer:

DiKsa [7]2 years ago

5 0

Answer: 10L

Explanation:

Given that:

Initial pressure P1 = 1 atm

New pressure P2 = 3 atm

Initial volume V2 = 30 L

New volume V2 = ?

Since pressure and volume are involved, apply the formula for Boyle's law

P1V1 = P2V2

1 atm x 30L = 3 atm x V2

30 atm L = 3 atm x V2

V2 = (30 atm L / 3 atm)

V2 = 10L

Thus, volume changed to 10 liters

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Lapatulllka [165]

Answer: 101 moles of oxygen are contained in the tank

Explanation:

According to ideal gas equation:

$PV=nRT$

P = pressure of gas = 204.047 atm

V = Volume of gas = 12.0 L

n = number of moles = ?

R = gas constant = $0.0821Latm/Kmol$

T =temperature = $22.0^0C=(22.0+273)K=295K$

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$n=\frac{204.047atm\times 12.0L}{0.0821 L atm/K mol\times 295K}=101moles$

Thus 101 moles of oxygen are contained in the tank

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Identify the acid and conjugate base pair in the following equation:

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1 year ago

Consider the equation: S+302 →SO3 Is this equation balanced? Why or why not?

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