So this can explain the density of a person very clearly.
Answer:
2 mol H₂O
Explanation:
With the reaction,
- 2H₂(g) + O₂(g) → 2 H₂O(g)
1.55 moles of O₂ would react completely with ( 2*1.55 ) 3.1 moles of H₂. There are not as many moles of H₂, thus H₂ is the limiting reactant.
Now we <u>calculate the moles of H₂O produced</u>, <em>starting from the moles of limiting reactant</em>:
- 2.00 mol H₂ *
= 2 mol H₂O
Answer:
3–methyl–2–butanol
Explanation:
To name the compound, we must:
1. Identify the functional group.
2. Give the functional group of the compound the lowest possible count.
3. Locate the longest continuous carbon chain. This gives the parent name of the compound.
4. Identify the substituent group attached.
5. Give the substituent group the lowest possible count.
6. Combine the above to get the name of the compound.
Now, let us obtain the name of the compound.
1. The functional group of the compound is Alcohol i.e —OH.
2. The functional group is located at carbon 2.
3. The longest continuous carbon chain is carbon 4 i.e butane. But the presence of the functional group i.e OH will replace the –e in butane with –ol. Therefore, the compound is butanol.
4. The substituent group attached is methyl i.e CH3.
5. The substituent group is located at carbon 3.
6. Therefore, the name of the compound is:
3–methyl–2–butanol.
In a voltaic cell there are two electrodes: anode and cathode.
On the cathode, the reaction that occurs is reduction, which means that the metal gains electrons.
On the anode the reaction is oxidation, which means that the metal loses electrons.
In this voltaic cell the reaction on the anode is:
Zn --> Zn 2+ + 2e-, i.e. option C.
Answer: option C.
Answer:
E.) +5
Explanation:
Oxygen always has -2 oxidation number.
Because there are 3 oxygen atoms present, this means oxygen is contributing a -6 charge (-2 x 3 = -6).
Therefore, since the overall molecule is -1, chlorine must have an oxidation number of +5 to cancel all of the negative charges but 1.
You can also think of the problem like an equation. In this equation, "x" is the oxidation number of chlorine, (-2) is the oxidation number of oxygen, (3) is the number of oxygen atoms present, and the equation is set equal to (-1) because that is the overall charge of the molecule.
x - 2(3) = -1
x - 6 = -1
x = 5
