Question

HELP PLEASE!!!!!

Answer 1

Answer:

C) 4moles

Explanation:

Let's consider the following balanced equation.

2 H₂S(g) + 3 O₂(g) → 2 SO₂(g) + 2 H₂O(g)

The molar ratio of O₂(g) to SO₂(g) is 3:2. The moles of SO₂(g) produced from the reaction of 6 moles of O₂(g) are:

6 mol O₂(g) × (2 mol SO₂(g)/ 3 mol O₂(g)) = 4 mol SO₂(g)

When 6 moles of O₂(g) react with more than enough H₂S(g), 4 moles of SO₂(g) are produced.

Answer 2

The balanced equation is expressed:

H2S + 3/2O2 --> SO2 + H2O 

We are given the amount of O2 to be used in the reaction. This will be the starting point for our calculations. We do as follows:

6 mol O2 ( 1 mol SO2 / 3/2 mol O2 ) = 4 moles SO2 produced

Hope this answers the question. Have a nice day.